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# Chief Hopper – HackerRank Solution Java , Python 3, Python 2 , C , C++, Best and Optimal Solutions , All you need.

# Solutions of Algorithms Data Structures Hard HackerRank:

## Here are all the Solutions of Hard , Advanced , Expert Algorithms of Data Structure of Hacker Rank , Leave a comment for similar posts

# C++ Chief Hopper HackerRank Solution

#include <vector> #include <list> #include <map> #include <set> #include <queue> #include <stack> #include <algorithm> #include <numeric> #include <utility> #include <sstream> #include <iostream> #include <iomanip> #include <cstdio> #include <cmath> #include <cstdlib> #include <ctime> #include <limits> #include <cstring> #include <string> using namespace std; #define pairii pair<int, int> #define llong long long #define pb push_back #define sortall(x) sort((x).begin(), (x).end()) #define INFI numeric_limits<int>::max() #define INFLL numeric_limits<llong>::max() #define INFD numeric_limits<double>::max() #define FOR(i,s,n) for (int (i) = (s); (i) < (n); (i)++) #define FORZ(i,n) FOR((i),0,(n)) const int MAXN = 100005; int ar[MAXN]; void solve() { int n; scanf("%d",&n); FORZ(i,n) scanf("%d",ar+i); int res = 0; for (int i = n-1; i >= 0; i--) { int x = res + ar[i]; res = x/2 + x%2; } printf("%d",res); } int main() { #ifdef DEBUG freopen("in.txt", "r", stdin); freopen("out.txt", "w", stdout); #endif solve(); return 0; }

# Java Chief Hopper HackerRank Solution

import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.util.StringTokenizer; public class Solution { private static class InputArray { final StringTokenizer strt; public final int length; InputArray(String str, int N){ strt = new StringTokenizer(str); length = N; } int next(){ return Integer.parseInt(strt.nextToken()); } } public static long solve(InputArray array) { long botEnergy = 0L; // initial bot energy long power2 = 1L; final long MAX_LIMIT = 2 << 18; long b = botEnergy; for (int i = 0; i < array.length && i < 30; ++i) { b = 2 * b - array.next(); if(b >= MAX_LIMIT) //after this no amount of input will make energy negative return botEnergy; power2 *= 2; if (b < 0) { // increase the initial botEnergy by a minimum amount necessary double dif = -1 * b; long x = Math.round(Math.floor(dif / power2)); for (long inc = 0; inc <= 10; ++inc) { long newb = power2 * (x + inc) + b; if (newb >= 0) { botEnergy += (x + inc); b = newb; break; } } } } for (int i = 30; i < array.length; ++i) { b = 2 * b - array.next(); if (b < 0) { botEnergy++; // after this increase bot energy can never become // smaller than 0 break; } } return botEnergy; } public static void main(String[] args) throws NumberFormatException, IOException { BufferedReader bfr = new BufferedReader(new InputStreamReader(System.in)); final int N = Integer.parseInt(bfr.readLine()); InputArray array = new InputArray(bfr.readLine(), N); System.out.println(solve(array)); } }

# Python 3 Chief Hopper HackerRank Solution

N = int(input()) H = [int(_) for _ in input().split()] i,b = len(H),H[-1] while i > 0 : i -= 1 b = (H[i]+b+1)//2 # print(b) print(b)

# Python 2 Chief Hopper HackerRank Solution

from math import ceil def validate(val): global n, h for i in xrange(n): val = ((val * 2) - h[i]) if val < 0: return False return True if __name__ == "__main__": n = int(raw_input()) h = map(int, raw_input().split()) i = 0 mx = max(h) result = mx + 1 start = 0 while start >= 0 and start <= mx: mid = ceil((start+mx)/2.0) if validate(mid): mx = mid if mid < result: result = mid else: break else: start = mid print int(result)

# C Chief Hopper HackerRank Solution

#include <stdio.h> #include <stdlib.h> int main() { int n, *h, i; unsigned long long tot; scanf("%d",&n); h = malloc(n * sizeof(int)); for (i=0; i<n; i++) scanf("%d",&h[i]); tot = 0; i--; while (i>=0) { tot += h[i]; if (tot & 1) tot++; tot /= 2; i--; } printf("%lld\n",tot); return 0; }

## Warmup

Implementation

Strings

Sorting

Search

Graph Theory

Greedy

Dynamic Programming

Constructive Algorithms

Bit Manipulation

Recursion

Game Theory

NP Complete

Debugging

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