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Home Code Solutions

Coin Change II – LeetCode Solution

Coin Change II - LeetCode Solution Java , Python 3, Python 2 , C , C++, Best and Optimal Solutions , All you need.

BhautikBhalala by BhautikBhalala
September 10, 2022
Reading Time: 2 mins read
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Leetcode All Problems Solutions

Leetcode All Problems Solutions

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Table of Contents

  • Coin Change II – LeetCode Solution Java , Python 3, Python 2 , C , C++, Best and Optimal Solutions , All you need.
  • C++ Coin Change II LeetCode Solution
  • Java Coin Change II LeetCode Solution
  • Python 3 Coin Change II LeetCode Solution
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Coin Change II – LeetCode Solution Java , Python 3, Python 2 , C , C++, Best and Optimal Solutions , All you need.

You are given an integer array coins representing coins of different denominations and an integer amount representing a total amount of money.

Return the number of combinations that make up that amount. If that amount of money cannot be made up by any combination of the coins, return 0.

You may assume that you have an infinite number of each kind of coin.

The answer is guaranteed to fit into a signed 32-bit integer.

 

Example 1:

Input: amount = 5, coins = [1,2,5]
Output: 4
Explanation: there are four ways to make up the amount:
5=5
5=2+2+1
5=2+1+1+1
5=1+1+1+1+1

Example 2:

Input: amount = 3, coins = [2]
Output: 0
Explanation: the amount of 3 cannot be made up just with coins of 2.

Example 3:

Input: amount = 10, coins = [10]
Output: 1

 

Constraints:

  • 1 <= coins.length <= 300
  • 1 <= coins[i] <= 5000
  • All the values of coins are unique.
  • 0 <= amount <= 5000

C++ Coin Change II LeetCode Solution


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class Solution {
public:
    
    int coinChange(vector<int>& coins, int n, int amount)
    {
        if(n==0)
            return 0;
        if(amount == 0)
        {
            return 1;
        }
        if(coins[n-1] > amount)
        {
            return coinChange(coins, n-1, amount);
        }
        return coinChange(coins, n, amount-coins[n-1]) + coinChange(coins, n-1, amount);
    }
    
    int change(int amount, vector<int>& coins) {
        int n = coins.size();
        if(amount == 0) {
            return 1;
        }
        if(n==0)
            return 0;
        return coinChange(coins, n, amount);
        
    }
};

Java Coin Change II LeetCode Solution


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class Solution {
    public int change(int amount, int[] coins) {
        Integer[][] dp = new Integer[coins.length][amount + 1];
        return dfs(coins, 0, amount, dp);
    }
    int dfs(int[] coins, int i, int amount, Integer[][] dp) {
        if (amount == 0) return 1;
        if (i == coins.length) return 0;
        if (dp[i][amount] != null) return dp[i][amount];
        int ans = dfs(coins, i + 1, amount, dp); // skip ith coin
        if (amount >= coins[i])
            ans += dfs(coins, i, amount - coins[i], dp); // use ith coin
        return dp[i][amount] = ans;
    }
}

 



Python 3 Coin Change II LeetCode Solution


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class Solution(object):
    def change(self, amount, coins):
        """
        :type amount: int
        :type coins: List[int]
        :rtype: int
        """
        #If we found a way to create the desired amount
        if amount == 0: 
            return 1 
        
        #If we went over our amount or we have no more coins left
        if amount < 0 or len(coins) == 0:
            return 0 

        #Our solutions can be divided into two sets,
        #   1) Solutions that cointain the coin at the end of the coins array 
        #   2) Solutions that don't contain that coin 
        return self.change(amount - coins[-1], coins) + self.change(amount, coins[:-1]) 



 

Array-1180
String-562
Hash Table-412
Dynamic Programming-390
Math-368
Sorting-264


Greedy-257
Depth-First Search-256
Database-215
Breadth-First Search-200
Tree-195


Binary Search-191
Matrix-176
Binary Tree-160
Two Pointers-151
Bit Manipulation-140


Stack-133
Heap (Priority Queue)-117
Design-116
Graph-108
Simulation-103
Prefix Sum-96


Backtracking-92
Counting-86
Sliding Window-73
Linked List-69
Union Find-66


Ordered Set-48
Monotonic Stack-47
Recursion-43
Trie-41
Binary Search Tree-40
Divide and Conquer-40


Enumeration-39
Bitmask-37
Queue-33
Memoization-32
Topological Sort-31


Geometry-30
Segment Tree-27
Game Theory-24
Hash Function-24
Binary Indexed Tree-21


Interactive-18
Data Stream-17
String Matching-17
Rolling Hash-17
Shortest Path-16


Number Theory-16
Combinatorics-15
Randomized-12
Monotonic Queue-9
Iterator-9
Merge Sort-9


Concurrency-9
Doubly-Linked List-8
Brainteaser-8
Probability and Statistics-7
Quickselect-7


Bucket Sort-6
Suffix Array-6
Minimum Spanning Tree-5
Counting Sort-5
Shell-4


Line Sweep-4
Reservoir Sampling-4
Eulerian Circuit-3
Radix Sort-3


Strongly Connected Componen-t2
Rejection Sampling-2
Biconnected Component-1

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Tags: Cc++14Coin Change IIfull solutionGojavajava 15java 7java 8java8javascriptkotlinLeetCodeLeetCodeSolutionpypy 3Python 2python 3rubyrustSolution
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