Table of Contents
Contains Duplicate – LeetCode Solution Java , Python 3, Python 2 , C , C++, Best and Optimal Solutions , All you need.
Given an integer array nums, return true if any value appears at least twice in the array, and return false if every element is distinct.
Example 1:
Input: nums = [1,2,3,1] Output: true
Example 2:
Input: nums = [1,2,3,4] Output: false
Example 3:
Input: nums = [1,1,1,3,3,4,3,2,4,2] Output: true
Constraints:
1 <= nums.length <= 105-109 <= nums[i] <= 109
C++ Contains Duplicate LeetCode Solution
#include <set>
using namespace std;
class Solution {
public:
bool containsDuplicate(vector<int>& nums) {
return nums.size() > set<int>(nums.begin(), nums.end()).size();
}
};
Java Contains Duplicate LeetCode Solution
public boolean containsDuplicate(int[] nums) {
Set<Integer> set = new HashSet<Integer>();
for(int i : nums)
if(!set.add(i))// if there is same
return true;
return false;
}
Python 3 Contains Duplicate LeetCode Solution
class Solution(object):
def containsDuplicate(self, nums):
"""
:type nums: List[int]
:rtype: bool
"""
return len(nums) != len(set(nums))
Array-1180
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