• Home
  • Top Posts
  • Code Solutions
  • How to
  • News
  • Trending
  • Anime
  • Health
  • Education
Friday, February 3, 2023
  • Login
Zeroplusfour
No Result
View All Result
  • Home
  • Top Posts
  • Code Solutions
  • How to
  • News
  • Trending
  • Anime
  • Health
  • Education
  • Home
  • Top Posts
  • Code Solutions
  • How to
  • News
  • Trending
  • Anime
  • Health
  • Education
No Result
View All Result
Zeroplusfour
No Result
View All Result
Home Code Solutions Hackerrank Algorithms

Count Scorecards – HackerRank Solution

Count Scorecards - HackerRank Solution Java , Python 3, Python 2 , C , C++, Best and Optimal Solutions , All you need.

admin by admin
August 24, 2022
Reading Time: 1 min read
0
15 Days to learn SQL Hard SQL(Advanced)-Solution

15 Days to learn SQL Hard SQL(Advanced)-Solution alt text

Spread the love

Table of Contents

  • Count Scorecards – HackerRank Solution Java , Python 3, Python 2 , C , C++, Best and Optimal Solutions , All you need.
  • Solutions of Algorithms Data Structures Hard HackerRank:
    • Here are all the Solutions of Hard , Advanced , Expert Algorithms of Data Structure of Hacker Rank , Leave a comment for similar posts
  • C++ replace HackerRank Solution
  • Java rep HackerRank Solution
  • Python 2 rep HackerRank Solution
  • Python 3 rep HackerRank Solution
  • C rep HackerRank Solution
    • Warmup Implementation Strings Sorting Search Graph Theory Greedy Dynamic Programming Constructive Algorithms Bit Manipulation Recursion Game Theory NP Complete Debugging
    • Leave a comment below
      • Related posts:

Count Scorecards – HackerRank Solution Java , Python 3, Python 2 , C , C++, Best and Optimal Solutions , All you need.

Solutions of Algorithms Data Structures Hard HackerRank:

Here are all the Solutions of Hard , Advanced , Expert Algorithms of Data Structure of Hacker Rank , Leave a comment for similar posts

C++ replace HackerRank Solution


Copy Code Copied Use a different Browser

/* Enter your code here. Read input from STDIN. Print output to STDOUT */
#include<iostream>
#include<vector>
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#include<algorithm>
using namespace std ;
#define MAXN 42
#define MOD 1000000007

int n ;
vector<int> G ;

int check(vector<int> gg)
{
 sort(gg.begin(),gg.end()) ;
 int sum = 0 ;
 for(int i = 0;i < n;i++)
 {
  sum += gg[i] ;
  if(sum < i * (i + 1) / 2) return 0 ;
 }
 return 1 ;
}

int solve1(int k,int sum)
{
 if(sum > n * (n - 1) / 2) return 0 ;
 if(k == n) return sum == n * (n - 1) / 2 && check(G) ? 1 : 0 ;
 if(G[k] != -1) return solve1(k + 1,sum + G[k]) ;
 
 int ret = 0 ;
 for(int i = 0;i < n;i++)
 {
  G[k] = i ;
  ret += solve1(k + 1,sum + i) ;
  G[k] = -1 ;
 }
 return ret ;
}

int solve1(vector<int> g)
{
 G = g ;
 n = G.size() ;
 int ret = solve1(0,0) ;
 return ret ;
}

int fac[MAXN],inv[MAXN] ;
int pow(int a,int b)
{
 if(b == 0) return 1 ;
 int ret = pow(a,b / 2) ;
 ret = 1LL * ret * ret % MOD ;
 if(b & 1) ret = 1LL * ret * a % MOD ;
 return ret ;
}

int occ[MAXN],big[MAXN] ;
int memo[MAXN][MAXN][MAXN * MAXN] ;
int solve2(int k,int last,int sum)
{
 if(last == n) return 0 ;
 if(sum > n * (n - 1) / 2) return 0 ;
 if(k == n) return big[last + 1] == 0 && sum == n * (n - 1) / 2 ? 1 : 0 ;
 if(memo[k][last + 1][sum] != -1) return memo[k][last + 1][sum] ;
 int occr = occ[last + 1] ;
 int ret = 0,added = 0 ;
 for(int i = 0;k + i <= n;i++)
 {
  if(sum + added < (k + i) * (k + i - 1) / 2) break ;
  if(i >= occr) ret += 1LL * inv[i - occr] * solve2(k + i,last + 1,sum + added) % MOD ;
  if(ret >= MOD) ret -= MOD ;
  added += last + 1 ;
 }
 return memo[k][last + 1][sum] = ret ;
}

int solve2(vector<int> g)
{
 fac[0] = inv[0] = 1 ;
 for(int i = 1;i < MAXN;i++)
 {
  fac[i] = 1LL * i * fac[i - 1] % MOD ;
  inv[i] = pow(fac[i],MOD - 2) ;
 }
 n = g.size() ;

 int start = 0 ;
 memset(occ,0,sizeof occ) ;
 memset(big,0,sizeof big) ;
 for(int i = 0;i < g.size();i++) if(g[i] != -1) occ[g[i]]++,start++ ;
 for(int i = 0;i < n;i++)
  for(int j = i;j < n;j++)
   big[i] += occ[j] ;
 memset(memo,255,sizeof memo) ;
 int ret = solve2(0,-1,0) ; 
 ret = 1LL * ret * fac[n - start] % MOD ;
 return ret ;
}


vector<int> gen()
{
 int n = rand() % 10 + 1 ;
 vector<int> ret ;
 for(int i = 0;i < n;i++)
 {
  if(rand() % 2 == 0) ret.push_back(-1) ;
  else ret.push_back(rand() % n) ;
 }
 return ret ;
}

void test()
{
 for(int t = 1;t < 100;t++)
 {
  vector<int> g = gen() ;
  int ret1 = solve1(g) ;
  int ret2 = solve2(g) ;

  cout << ret1 << " " << ret2 << endl ;
  if(ret1 != ret2)
  {
   cout << "failed on: " << t << endl ;
   cout << g.size() << " : " ;
   for(int i = 0;i < g.size();i++) cout << g[i] << " " ; cout << endl ;
   while(1) ;
  }
 }
}

void generate()
{
 char in[] = "in .txt" ;
 for(int test = 0;test < 10;test++)
 {
  in[2] = test + '0' ;
  FILE * fout = fopen(in,"w") ;
  int runs = 20 ;
  fprintf(fout,"%d\n",runs) ;
  for(int t = 0;t < runs;t++)
  {
   if(rand() % 3 != 0) n = rand() % 40 + 1 ;
   else n = 40 - rand() % 10 ;
   int per = 70 ;
   
   vector<int> g ;
   for(int i = 0;i < n;i++)
   {
    if(rand() % 100 < per) g.push_back(-1) ;
    else g.push_back(rand() % n) ;
   }

   fprintf(fout,"%d\n",n) ;
   for(int i = 0;i < n;i++)
   {
    if(i) fprintf(fout," ") ;
    fprintf(fout,"%d",g[i]) ;
   }
   fprintf(fout,"\n") ;
  }
 }
}

int main()
{
// srand(time(NULL)) ; 
// generate() ; return 0 ;
// test() ; return 0 ;
 
 int runs ;
 cin >> runs ;
 while(runs--)
 {
  int n ;
  vector<int> g ;
  cin >> n ;
  for(int i = 0;i < n;i++)
  {
   int k ;
   cin >> k ;
   g.push_back(k) ;
  }
  int ret = solve2(g) ;
  printf("%d\n",ret) ;
 } 
 return 0 ;
}

Java rep HackerRank Solution


Copy Code Copied Use a different Browser

import java.io.*;
import java.util.*;

public class Solution {

    // leave empty to read from stdin/stdout
    private static final String TASK_NAME_FOR_IO = "";

    // file names
    private static final String FILE_IN = TASK_NAME_FOR_IO + ".in";
    private static final String FILE_OUT = TASK_NAME_FOR_IO + ".out";

    BufferedReader in;
    PrintWriter out;
    StringTokenizer tokenizer = new StringTokenizer("");

    public static void main(String[] args) {
        new Solution().run();
    }

    class State {

        int[] a;

        State(int[] a) {
            this.a = a.clone();
            Arrays.sort(this.a);
        }

        @Override
        public boolean equals(Object o) {
            if (this == o) return true;
            if (o == null || getClass() != o.getClass()) return false;

            State state = (State) o;

            if (!Arrays.equals(a, state.a)) return false;

            return true;
        }

        @Override
        public int hashCode() {
            return a != null ? Arrays.hashCode(a) : 0;
        }

        @SuppressWarnings({"ForLoopReplaceableByForEach"})
        public int[] contains(int[] fixed) {
            int rPos = 0;
            int[] remaining = new int[a.length];

            int fPos = 0;
            for (int i = 0; i < a.length; i++)
                if (fPos < fixed.length && a[i] == fixed[fPos]) {
                    fPos++;
                } else {
                    remaining[rPos++] = a[i];
                }

            if (fPos < fixed.length) {
                return null;
            }

            int[] result = new int[rPos];
            System.arraycopy(remaining, 0, result, 0, rPos);
            return result;
        }

        @Override
        public String toString() {
            StringBuilder result = new StringBuilder();
            for (int v : a) {
                if (result.length() > 0) {
                    result.append(' ');
                }
                result.append(Integer.toString(v));
            }
            return result.toString();
        }
    }

    static final int MOD = 1000000007;

    int n;

    // http://mathworld.wolfram.com/ScoreSequence.html
    private void solve() throws IOException {
        // stress();
        // timing();

        int tc = nextInt();
        for (int tcIdx = 0; tcIdx < tc; tcIdx++) {
            n = nextInt();

            List<Integer> fixedList = new ArrayList<Integer>();
            for (int i = 0; i < n; i++) {
                int k = nextInt();
                if (k >= 0) {
                    fixedList.add(k);
                }
            }

            int[] fixed = new int[fixedList.size()];
            for (int i = 0; i < fixedList.size(); i++) {
                fixed[i] = fixedList.get(i);
            }
            Arrays.sort(fixed);

            out.println(solveFast(fixed));
            // out.println(solveFast(fixed) + " - " + solveNaive(fixed));
        }

    }

    private void stress() {
        Random r = new Random(123456789L);

        int tcNum = 100000;
        for (int tcIdx = 0; tcIdx < tcNum; tcIdx++) {
            n = 1 + r.nextInt(14);
            System.out.print("Stress #" + tcIdx + ": n = " + n);

            int len = r.nextInt(n + 1);
            int[] fixed = new int[len];
            for (int i = 0; i < len; i++) {
                fixed[i] = r.nextInt(n);
            }
            Arrays.sort(fixed);

            System.out.println(", answers: " + solveFast(fixed) + " vs. " + solveNaive(fixed));
        }

    }

    private void timing() {
        Random r = new Random(123456789L);

        int tcNum = 20;
        for (int tcIdx = 0; tcIdx < tcNum; tcIdx++) {
            n = 40;
            System.out.print("Timing #" + tcIdx + ": n = " + n);

            int len = 0;
            int[] fixed = new int[len];
            for (int i = 0; i < len; i++) {
                fixed[i] = r.nextInt(n);
            }
            Arrays.sort(fixed);

            System.out.println(", answers: " + solveFast(fixed));
        }

    }

    static final int MAXM = 100;
    static long[][] CNK;

    static {
        CNK = new long[MAXM][MAXM];
        for (int n = 0; n < MAXM; n++) {
            CNK[n][0] = 1;
            CNK[n][n] = 1;
            for (int k = 1; k < n; ++k) {
                CNK[n][k] = CNK[n - 1][k - 1] + CNK[n - 1][k];
                CNK[n][k] %= MOD;
            }
        }
    }

    private int solveFast(int[] fixed) {
        // d[len][fLen][min][sumRem]:
        //   we processed 'len' symbols so far
        //   out of them 'fLen' were taken from string 'fixed' -- we can actually calculate this one dynamically
        //   last used group of elements had value les than 'min'
        //   total sum remaining is equal to 'sum'
        int nSum = (n * (n - 1)) / 2;

        int[][][] d = new int[n + 1][n + 1][nSum + 1];
        d[0][0][nSum] = 1;

        for (int len = 0; len < n; len++)
            for (int min = 0; min < n; min++) {

                int fLen = 0;
                while (fLen < fixed.length && fixed[fLen] < min) {
                    fLen++;
                }

                int fCnt = 0;
                while (fLen + fCnt < fixed.length && fixed[fLen + fCnt] == fixed[fLen]) {
                    fCnt++;
                }

                for (int sumRem = 0; sumRem <= nSum; sumRem++)
                    if (d[len][min][sumRem] > 0) {

                        // we are definitely taking >= "min"
                        int lo = min;

                        // but we can't really take more than the next element of 'fixed'
                        int hi = fLen < fixed.length ? fixed[fLen] : n - 1;

                        // let's iterate over the element that we will put
                        for (int put = lo; put <= hi; put++) {

                            // what sum do we currently have
                            int sumBase = nSum - sumRem;

                            // determine minimum count, by presence in fixed array
                            int fCntMin = 0;
                            if (fLen < fixed.length && put == fixed[fLen]) {
                                fCntMin = fCnt;
                            }

                            int cnt = 1;
                            int sumCur = 0;
                            while (len + cnt <= n) {
                                // place the element, increase the sum
                                sumCur += put;

                                // but there is a lower limit  on the sum, based on the position
                                int sumMin = ( (len + cnt - 1) * (len + cnt)) / 2;

                                // if criteria is not met, then there is no reason to continue
                                if (sumBase + sumCur < sumMin) {
                                    break;
                                }

                                // if we took too much, then there is no reason to continue either
                                if (sumRem - sumCur - (n - (len + cnt)) * put < 0) {
                                    break;
                                }

                                // start updating?
                                if (cnt >= fCntMin) {
                                    // already placed:
                                    //   * len characters
                                    //
                                    // we are placing additionally:
                                    //   * fCntMin is the number of elements we are taking from 'fixed'
                                    //   * (cnt - fCntMin) is the number of wildcard elements we are adding
                                    //
                                    // so:
                                    //   * (len + fCntMin) will be occupied by previous characters + fixed characters
                                    //   * n - (len + fCntMin) is the remaining space (wildcards & non-wildcards)
                                    //   * n - (len + fCntMin) - (fixed.length - (fLen + fCntMin)) is the remaining space for wildcards


                                    int wildcardPlaces = n - (len + fCntMin) - (fixed.length - (fLen + fCntMin));
                                    int wildcardChars = cnt - fCntMin;
                                    long addon = CNK[wildcardPlaces][wildcardChars] * d[len][min][sumRem];
                                    d[len + cnt][put + 1][sumRem - sumCur] += addon % MOD;
                                    if (d[len + cnt][put + 1][sumRem - sumCur] >= MOD) {
                                        d[len + cnt][put + 1][sumRem - sumCur] -= MOD;
                                    }
                                }

                                cnt++;
                            }

                        }

                    }
            }

        int result = 0;
        int lo = fixed.length > 0 ? fixed[fixed.length - 1] + 1 : 0;
        for (int min = lo; min <= n; min++) {
            result += d[n][min][0];
            if (result >= MOD) {
                result -= MOD;
            }
        }
        return result;
    }

    private int solveNaive(int[] fixed) {

        buf = new int[n];
        states = new HashSet<State>();
        rec(0, 0, 0);

        int result = 0;
        for (State state : states) {
            int[] remaining = state.contains(fixed);
            if (remaining != null) {
                long fLen = fact(remaining.length);

                int[] cnt = new int[n];
                for (int v : remaining) {
                    cnt[v]++;
                }

                for (int v : cnt)
                    if (v > 1) {
                        fLen /= fact(v);
                    }

                result += fLen % MOD;
                result %= MOD;

                // System.out.println(state.toString() + ": " + fLen);
            }
        }

        // System.out.println("***");

        return result;
    }

    private long fact(int k) {
        long result = 1;
        for (int i = 2; i <= k; i++) {
            result *= i;
        }
        return result;
    }

    Set<State> states;
    int[] buf;

    @SuppressWarnings({"UnusedDeclaration"})
    private void printAll() {
        for (n = 1; n <= 20; n++) {
            System.out.println("n = " + n + ":");

            buf = new int[n];
            states = new HashSet<State>();
            rec(0, 0, 0);

            /*
            for (State s : states) {
                System.out.print("    ");
                for (int v : s.a) {
                    System.out.print(v + " ");
                }
                System.out.println();
            }
            */
            System.out.println("    cnt = " + states.size());
        }
    }

    private void rec(int k, int min, int sum) {
        if (k >= n) {

            int sumTarget = (k * (k - 1)) / 2;
            if (sum == sumTarget) {
                states.add(new State(buf));
            }

            return;
        }

        int sumMin = (k * (k + 1)) / 2;
        for (int v = min; v < n; v++)
            if (sum + v >= sumMin) {
                buf[k] = v;
                rec(k + 1, v, sum + v);
            }
    }

    public void run() {
        long timeStart = System.currentTimeMillis();

        boolean fileIO = TASK_NAME_FOR_IO.length() > 0;
        try {

            if (fileIO) {
                in = new BufferedReader(new FileReader(FILE_IN));
                out = new PrintWriter(new FileWriter(FILE_OUT));
            } else {
                in = new BufferedReader(new InputStreamReader(System.in));
                out = new PrintWriter(new OutputStreamWriter(System.out));
            }

            solve();

            in.close();
            out.close();
        } catch (IOException e) {
            throw new IllegalStateException(e);
        }
        long timeEnd = System.currentTimeMillis();

        if (fileIO) {
            System.out.println("Time spent: " + (timeEnd - timeStart) + " ms");
        }
    }

    private String nextToken() throws IOException {
        while (!tokenizer.hasMoreTokens()) {
            String line = in.readLine();
            if (line == null) {
                return null;
            }
            tokenizer = new StringTokenizer(line);
        }
        return tokenizer.nextToken();
    }

    private int nextInt() throws IOException {
        return Integer.parseInt(nextToken());
    }

}

 



Python 2 rep HackerRank Solution


Copy Code Copied Use a different Browser

f = lambda n:n-1 + abs(n-1) and f(n-1)*long(n) or 1

def main():
    ncases = int(raw_input())
    for n in range(ncases):
        raw_input()
        case = [int(x) for x in raw_input().split()]
        N = len(case)
        L = case.count(-1)
        cm = [case.count(d) for d in range(N)]
        print get_counts(N, L, cm).get((N, N*(N-1)/2), 0) % 1000000007

def get_counts(N, L, cm):
    """
    Iteratively generate solutions that satisfy two constraints.

    N   is the overall length of the scorecard.
    L   is the number of omitted scores.
    cm  is the minimum number of counts of each score, based on the scores that
        are not omitted.

    Here on, S1 is the length of the score set, and S2 is the sum of scores.
    New score sets are generated by considering all possible counts of scores
    equal to m.  Such a score count is considered possible if it satisfies
    Landau's theorem for tournaments (1953).
    """
    S1max = N
    S2max = N*(N-1)/2
    C = {(0, 0) : f(L)}
    for m in range(N):
        Cn = {}
        for (s1, s2), c in C.iteritems():
            n = cm[m]
            i = 0
            fct = 1
            S1 = s1+n
            S2 = s2+m*n
            while S1*(S1-1)/2 <= S2 <= S2max:
                Cn[(S1, S2)] = Cn.get((S1, S2), 0) + c/fct
                #big = Cn.get((S1, S2), 0) + c/fct
                #Cn[(S1, S2)] = big  % 1000000007
                n += 1
                i += 1
                fct *= i
                S1 = s1+n
                S2 = s2+m*n
        C = Cn
    return C

if __name__ == '__main__':
    main()



Python 3 rep HackerRank Solution


Copy Code Copied Use a different Browser

 



C rep HackerRank Solution


Copy Code Copied Use a different Browser

/* Enter your code here. Read input from STDIN. Print output to STDOUT */
#include <stdio.h>
#include <stdlib.h>

#define P 1000000007
#define N 450

long long bin[50][50],jj,kk,h,ll,ii,t,a[50][50][1010],i,j,k,l,m,n,c[100],b[100];


int com(const void * xx, const void *yy)
{
if(*(long long *)xx < *(long long*)yy) return 1;
return -1;
}

int main()
{

for(i=0;i<50;i++) bin[i][0] = bin[i][i]=1;
for(i=1;i<50;i++)
 for(j=1;j<i;j++) bin[i][j] = (bin[i-1][j-1]+ bin[i-1][j])%P;

scanf("%lld",&t);
while(t--)
{
scanf("%lld",&n);
for(i=0;i<n;i++) scanf("%lld",&c[i]);

qsort(c,n,sizeof(c[0]),com);

for(i=0;i<=n;i++) b[i]=0; 

m=0;
for(i=0;i<n;i++) if(c[i]!=-1) b[c[i]]++; else m++;


for(i=0;i<=n;i++) 
 for(j=0;j<=n;j++) 
  for(k=0;k<=N;k++) a[i][j][k]=0;

a[n][0][0] = 1;
l=0;

for(i=n-1;i>=0;i--) 
{
 for(j=0;j<=m;j++)
 {
  h=0;
  ll=l;
  for(ii=0;ii<b[i];ii++)
    {
    h += (n-ll-j-1) - i;
    ll++;
    }
 
// printf("%lld %lld h %lld %lld=l\n",i,j,h,l);
 
  for(k=0;k<=N;k++) 
   if(k+h>=0) a[i][j][k+h] = (a[i][j][k+h] + a[i+1][j][k])%P;
}

//for(ii=0;ii<=n;ii++)
// for(jj=0;jj<=m;jj++)
//  for(kk=0;kk<=1000;kk++)
//   if(a[ii][jj][kk]) printf("%lld %lld %lld -> %lld\n", ii,jj,kk,a[ii][jj][kk]);
//printf("stred -----------%lld\n",i);



 // continue;
 
 for(j=m;j>=0;j--)
  for(k=0;k<N;k++)
    {
    h = k;
    for(jj=1;jj<=j && h>=0;jj++)
     {
     h -= (n-l-b[i]-(j-jj)-1) - i;
     
     if(h<0) break;
     
     a[i][j][k] = (a[i][j][k] + bin[m-j+jj][jj]*a[i][j-jj][h])%P;
//    if(a[i][j-jj][h]>0)     printf("...%lld=i %lld=j %lld=k %lld=jj %lld=h\n",i,j,k,jj,h);     
     }
}

//for(ii=0;ii<=n;ii++)
// for(jj=0;jj<=m;jj++)
//  for(kk=0;kk<=1000;kk++)
//   if(a[ii][jj][kk]) printf("%lld %lld %lld -> %lld\n", ii,jj,kk,a[ii][jj][kk]);

//printf("-----------%lld\n",i);
 
l+=b[i];
}

/*
for(i=0;i<=n;i++)
 for(j=0;j<=m;j++)
  for(k=0;k<=1000;k++)
   if(a[i][j][k]) printf("%lld %lld %lld -> %lld\n", i,j,k,a[i][j][k]);


for(i=0;i<=n;i++) printf("%lld %lld\n",i,c[i]);
*/
printf("%lld\n",(a[0][m][0]+P)%P);
//return 0;

}


return 0;
}

 

Warmup
Implementation
Strings
Sorting
Search
Graph Theory
Greedy
Dynamic Programming
Constructive Algorithms
Bit Manipulation
Recursion
Game Theory
NP Complete
Debugging

Leave a comment below

 

Related posts:

15 Days to learn SQL Hard SQL(Advanced)-SolutionDistant Pairs – HackerRank Solution 15 Days to learn SQL Hard SQL(Advanced)-SolutionThe Value of Friendship – HackerRank Solution 15 Days to learn SQL Hard SQL(Advanced)-SolutionDrive – HackerRank Solution 15 Days to learn SQL Hard SQL(Advanced)-SolutionQueens on Board – HackerRank Solution 15 Days to learn SQL Hard SQL(Advanced)-SolutionRecursive Digit Sum – HackerRank Solution 15 Days to learn SQL Hard SQL(Advanced)-SolutionHackerland Radio Transmitters – HackerRank Solution
Tags: Cc++14Count Scorecardsfull solutionGoHackerRank Solutionjavajava 15java 7java 8java8javascriptpypy 3Python 2python 3
ShareTweetPin
admin

admin

Related Posts

Leetcode All Problems Solutions
Code Solutions

Exclusive Time of Functions – LeetCode Solution

by admin
October 5, 2022
0
30

Exclusive Time of Functions - LeetCode Solution Java , Python 3, Python 2 , C , C++, Best and Optimal Solutions...

Read more
Leetcode All Problems Solutions

Smallest Range Covering Elements from K Lists – LeetCode Solution

October 5, 2022
32
Leetcode All Problems Solutions

Course Schedule III – LeetCode Solution

October 5, 2022
27
Leetcode All Problems Solutions

Maximum Product of Three Numbers – LeetCode Solution

September 11, 2022
53
Leetcode All Problems Solutions

Task Scheduler – LeetCode Solution

September 11, 2022
119
Leetcode All Problems Solutions

Valid Triangle Number – LeetCode Solution

September 11, 2022
28
Next Post
15 Days to learn SQL Hard SQL(Advanced)-Solution

Vim War - HackerRank Solution

15 Days to learn SQL Hard SQL(Advanced)-Solution

Best spot - HackerRank Solution

Leave a Reply Cancel reply

Your email address will not be published. Required fields are marked *

You may also like

15 Days to learn SQL Hard SQL(Advanced)-SolutionDistant Pairs – HackerRank Solution 15 Days to learn SQL Hard SQL(Advanced)-SolutionThe Value of Friendship – HackerRank Solution 15 Days to learn SQL Hard SQL(Advanced)-SolutionDrive – HackerRank Solution 15 Days to learn SQL Hard SQL(Advanced)-SolutionQueens on Board – HackerRank Solution 15 Days to learn SQL Hard SQL(Advanced)-SolutionRecursive Digit Sum – HackerRank Solution 15 Days to learn SQL Hard SQL(Advanced)-SolutionHackerland Radio Transmitters – HackerRank Solution

Categories

  • Algorithms
  • Anime
  • Biography
  • Business
  • Code Solutions
  • Cosmos
  • Countdowns
  • Culture
  • Economy
  • Education
  • Entertainment
  • Finance
  • Games
  • Hackerrank
  • Health
  • How to
  • Investment
  • LeetCode
  • Lifestyle
  • LINUX SHELL
  • Manga
  • News
  • Opinion
  • Politics
  • Sports
  • SQL
  • Tech
  • Travel
  • Uncategorized
  • Updates
  • World
  • DMCA
  • Home
  • My account
  • Privacy Policy
  • Top Posts

Recent Blogs

Leetcode All Problems Solutions

Exclusive Time of Functions – LeetCode Solution

October 5, 2022
Leetcode All Problems Solutions

Smallest Range Covering Elements from K Lists – LeetCode Solution

October 5, 2022
Biography

Charlotte Flair Net Worth, Age, Height , Achivements and more

September 8, 2022
0
Leetcode All Problems Solutions
Code Solutions

Find Duplicate File in System – LeetCode Solution

September 11, 2022
50
Top 10 Best Yoga poses alt textevery girl needs to know
Health

Top 10 Best Yoga poses every girl needs to know

May 31, 2022
2
Kakegurui
Anime

Top 10 Most Entertaining Kakegurui characters

May 12, 2022
11

© 2022 ZeroPlusFour - Latest News & Blog.

No Result
View All Result
  • Home
  • Category
    • Business
    • Culture
    • Economy
    • Lifestyle
    • Health
    • Travel
    • Opinion
    • Politics
    • Tech
  • Landing Page
  • Support Forum
  • Contact Us

© 2022 ZeroPlusFour - Latest News & Blog.

Welcome Back!

Login to your account below

Forgotten Password?

Retrieve your password

Please enter your username or email address to reset your password.

Log In
We use cookies on our website to give you the most relevant experience by remembering your preferences and repeat visits. By clicking “Accept All”, you consent to the use of ALL the cookies. However, you may visit "Cookie Settings" to provide a controlled consent.
Cookie SettingsAccept All
Manage consent

Privacy Overview

This website uses cookies to improve your experience while you navigate through the website. Out of these, the cookies that are categorized as necessary are stored on your browser as they are essential for the working of basic functionalities of the website. We also use third-party cookies that help us analyze and understand how you use this website. These cookies will be stored in your browser only with your consent. You also have the option to opt-out of these cookies. But opting out of some of these cookies may affect your browsing experience.
Necessary
Always Enabled
Necessary cookies are absolutely essential for the website to function properly. These cookies ensure basic functionalities and security features of the website, anonymously.
CookieDurationDescription
cookielawinfo-checkbox-analytics11 monthsThis cookie is set by GDPR Cookie Consent plugin. The cookie is used to store the user consent for the cookies in the category "Analytics".
cookielawinfo-checkbox-functional11 monthsThe cookie is set by GDPR cookie consent to record the user consent for the cookies in the category "Functional".
cookielawinfo-checkbox-necessary11 monthsThis cookie is set by GDPR Cookie Consent plugin. The cookies is used to store the user consent for the cookies in the category "Necessary".
cookielawinfo-checkbox-others11 monthsThis cookie is set by GDPR Cookie Consent plugin. The cookie is used to store the user consent for the cookies in the category "Other.
cookielawinfo-checkbox-performance11 monthsThis cookie is set by GDPR Cookie Consent plugin. The cookie is used to store the user consent for the cookies in the category "Performance".
viewed_cookie_policy11 monthsThe cookie is set by the GDPR Cookie Consent plugin and is used to store whether or not user has consented to the use of cookies. It does not store any personal data.
Functional
Functional cookies help to perform certain functionalities like sharing the content of the website on social media platforms, collect feedbacks, and other third-party features.
Performance
Performance cookies are used to understand and analyze the key performance indexes of the website which helps in delivering a better user experience for the visitors.
Analytics
Analytical cookies are used to understand how visitors interact with the website. These cookies help provide information on metrics the number of visitors, bounce rate, traffic source, etc.
Advertisement
Advertisement cookies are used to provide visitors with relevant ads and marketing campaigns. These cookies track visitors across websites and collect information to provide customized ads.
Others
Other uncategorized cookies are those that are being analyzed and have not been classified into a category as yet.
SAVE & ACCEPT
Are you sure want to unlock this post?
Unlock left : 0
Are you sure want to cancel subscription?