Heaters – LeetCode Solution Java , Python 3, Python 2 , C , C++, Best and Optimal Solutions , All you need.
Winter is coming! During the contest, your first job is to design a standard heater with a fixed warm radius to warm all the houses.
Every house can be warmed, as long as the house is within the heater’s warm radius range.
Given the positions of houses and heaters on a horizontal line, return the minimum radius standard of heaters so that those heaters could cover all houses.
Notice that all the heaters follow your radius standard, and the warm radius will the same.
Example 1:
Input: houses = [1,2,3], heaters = [2] Output: 1 Explanation: The only heater was placed in the position 2, and if we use the radius 1 standard, then all the houses can be warmed.
Example 2:
Input: houses = [1,2,3,4], heaters = [1,4] Output: 1 Explanation: The two heater was placed in the position 1 and 4. We need to use radius 1 standard, then all the houses can be warmed.
Example 3:
Input: houses = [1,5], heaters = [2] Output: 3
Constraints:
1 <= houses.length, heaters.length <= 3 * 1041 <= houses[i], heaters[i] <= 109
C++ Heaters LeetCode Solution
Here, A = houses and H = heaters.
class Solution {
public:
/*
Example: h = house, * = heater M = INT_MAX
h h h h h h h h h houses
1 2 3 4 5 6 7 8 9 index
* * * heaters
0 2 1 0 1 0 - - - (distance to nearest RHS heater)
0 1 2 0 1 0 1 2 3 (distance to nearest LHS heater)
0 1 1 0 1 0 1 2 3 (res = minimum of above two)
Result is maximum value in res, which is 3.
*/
int findRadius(vector<int>& A, vector<int>& H) {
sort(A.begin(), A.end());
sort(H.begin(), H.end());
vector<int> res(A.size(), INT_MAX);
// For each house, calculate distance to nearest RHS heater
for (int i = 0, h = 0; i < A.size() && h < H.size(); ) {
if (A[i] <= H[h]) { res[i] = H[h] - A[i]; i++; }
else { h++; }
}
// For each house, calculate distance to nearest LHS heater
for (int i = A.size()-1, h = H.size()-1; i >= 0 && h >= 0; ) {
if (A[i] >= H[h]) { res[i] = min(res[i], A[i] - H[h]); i--; }
else { h--; }
}
return *max_element(res.begin(), res.end());
}
};
Java Heaters LeetCode Solution
public class Solution {
public int findRadius(int[] houses, int[] heaters) {
Arrays.sort(heaters);
int result = Integer.MIN_VALUE;
for (int house : houses) {
int index = Arrays.binarySearch(heaters, house);
if (index < 0) {
index = -(index + 1);
}
int dist1 = index - 1 >= 0 ? house - heaters[index - 1] : Integer.MAX_VALUE;
int dist2 = index < heaters.length ? heaters[index] - house : Integer.MAX_VALUE;
result = Math.max(result, Math.min(dist1, dist2));
}
return result;
}
}
Python 3 HeatersLeetCode Solution
def findRadius(self, houses, heaters):
heaters.sort()
return max(min(abs(house - heater)
for i in [bisect.bisect(heaters, house)]
for heater in heaters[i-(i>0):i+1])
for house in houses)
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