Maximum Subarray – LeetCode Solution Java , Python 3, Python 2 , C , C++, Best and Optimal Solutions , All you need.
Given an integer array nums, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum.
A subarray is a contiguous part of an array.
Example 1:
Input: nums = [-2,1,-3,4,-1,2,1,-5,4] Output: 6 Explanation: [4,-1,2,1] has the largest sum = 6.
Example 2:
Input: nums = [1] Output: 1
Example 3:
Input: nums = [5,4,-1,7,8] Output: 23
Constraints:
1 <= nums.length <= 105-104 <= nums[i] <= 104
C++ Maximum Subarray LeetCode Solution
class Solution {
public:
int maxSubArray(vector<int>& nums) {
int n = size(nums), ans = INT_MIN;
for(int i = 0; i < n; i++)
for(int j = i, curSum = 0; j < n ; j++)
curSum += nums[j],
ans = max(ans, curSum);
return ans;
}
};
Java Maximum Subarray LeetCode Solution
public static int maxSubArray(int[] A) {
int maxSoFar=A[0], maxEndingHere=A[0];
for (int i=1;i<A.length;++i){
maxEndingHere= Math.max(maxEndingHere+A[i],A[i]);
maxSoFar=Math.max(maxSoFar, maxEndingHere);
}
return maxSoFar;
}
Python 3 Maximum Subarray LeetCode Solution
class Solution:
def maxSubArray(self, nums):
ans = -inf
for i in range(len(nums)):
cur_sum = 0
for j in range(i, len(nums)):
cur_sum += nums[j]
ans = max(ans, cur_sum)
return ans
Array-1180
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