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New Companies MediumSQL (Intermediate) – HackerRank Solution SQL, Best and Optimal Solutions , All you need.
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SQL New Companies MediumSQL (Intermediate) HackerRank Solution
select c.company_code,c.founder,
(select count(*) from Lead_Manager where company_code=c.company_code ) ,
(select count(*) from Senior_Manager where company_code=c.company_code ),
(select count(*) from Manager where company_code=c.company_code ),
(select count(*) from Employee where company_code=c.company_code )
from Company as c order by c.company_code
SQL (Basic)
SQL (Intermediate)
SQL (Advanced)
Basic Select
Advanced Select
Aggregation
Basic Join
Advanced Join
Alternative Queries
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