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Home Code Solutions

Perfect Rectangle – LeetCode Solution

Perfect Rectangle - LeetCode Solution Java , Python 3, Python 2 , C , C++, Best and Optimal Solutions , All you need.

admin by admin
September 8, 2022
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Leetcode All Problems Solutions

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Table of Contents

  • Perfect Rectangle – LeetCode Solution Java , Python 3, Python 2 , C , C++, Best and Optimal Solutions , All you need.
  • C++ Perfect Rectangle LeetCode Solution
  • Java Perfect Rectangle LeetCode Solution
  • Python 3 Perfect Rectangle LeetCode Solution
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Perfect Rectangle – LeetCode Solution Java , Python 3, Python 2 , C , C++, Best and Optimal Solutions , All you need.

Given an array rectangles where rectangles[i] = [xi, yi, ai, bi] represents an axis-aligned rectangle. The bottom-left point of the rectangle is (xi, yi) and the top-right point of it is (ai, bi).

Return true if all the rectangles together form an exact cover of a rectangular region.

 

Example 1:

Input: rectangles = [[1,1,3,3],[3,1,4,2],[3,2,4,4],[1,3,2,4],[2,3,3,4]]
Output: true
Explanation: All 5 rectangles together form an exact cover of a rectangular region.

Example 2:

Input: rectangles = [[1,1,2,3],[1,3,2,4],[3,1,4,2],[3,2,4,4]]
Output: false
Explanation: Because there is a gap between the two rectangular regions.

Example 3:

Input: rectangles = [[1,1,3,3],[3,1,4,2],[1,3,2,4],[2,2,4,4]]
Output: false
Explanation: Because two of the rectangles overlap with each other.

 

Constraints:

  • 1 <= rectangles.length <= 2 * 104
  • rectangles[i].length == 4
  • -105 <= xi, yi, ai, bi <= 105

C++ Perfect Rectangle LeetCode Solution


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class Solution {
private:
    struct comp {
        bool operator () (const pair<int, int>& a, const pair<int, int>& b) { return a.second <= b.first; }
    };
    
public:
    bool isRectangleCover(vector<vector<int>>& rectangles) {
        int area = 0, xmin = INT_MAX, ymin = INT_MAX, xmax = INT_MIN, ymax = INT_MIN;
        vector<vector<int>> verticalEdges;  // x, insertion/deletion event, ysmall, ylarge
        multiset<pair<int, int>, comp> s;   // for detecting overlaps
        
        // Calculate area, and configure verticalEdges
        for (auto v : rectangles) {
            area += (v[2] - v[0]) * (v[3] - v[1]);
            xmin = min(xmin, v[0]), ymin = min(ymin, v[1]), xmax = max(xmax, v[2]), ymax = max(ymax, v[3]);
            verticalEdges.push_back({v[0], 1, v[1], v[3]}), verticalEdges.push_back({v[2], -1, v[1], v[3]});
        }
        if (area != (xmax - xmin) * (ymax - ymin)) { return false; }
        
        // Check if any overlap exists
        sort(verticalEdges.begin(), verticalEdges.end());
        for (auto v : verticalEdges) {
            auto it = s.find(make_pair(v[2], v[3]));
            if (v[1] > 0) {                             // left edge, insertion event
                if (it != s.end()) { return false; }    // found an overlap
                s.insert(make_pair(v[2], v[3]));
            } else {                                    // right edge, deletion event
                s.erase(it);
            }
        }
        return true;
    }
};

Java Perfect Rectangle LeetCode Solution


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public boolean isRectangleCover(int[][] rectangles) {

        if (rectangles.length == 0 || rectangles[0].length == 0) return false;

        int x1 = Integer.MAX_VALUE;
        int x2 = Integer.MIN_VALUE;
        int y1 = Integer.MAX_VALUE;
        int y2 = Integer.MIN_VALUE;
        
        HashSet<String> set = new HashSet<String>();
        int area = 0;
        
        for (int[] rect : rectangles) {
            x1 = Math.min(rect[0], x1);
            y1 = Math.min(rect[1], y1);
            x2 = Math.max(rect[2], x2);
            y2 = Math.max(rect[3], y2);
            
            area += (rect[2] - rect[0]) * (rect[3] - rect[1]);
            
            String s1 = rect[0] + " " + rect[1];
            String s2 = rect[0] + " " + rect[3];
            String s3 = rect[2] + " " + rect[3];
            String s4 = rect[2] + " " + rect[1];
            
            if (!set.add(s1)) set.remove(s1);
            if (!set.add(s2)) set.remove(s2);
            if (!set.add(s3)) set.remove(s3);
            if (!set.add(s4)) set.remove(s4);
        }
        
        if (!set.contains(x1 + " " + y1) || !set.contains(x1 + " " + y2) || !set.contains(x2 + " " + y1) || !set.contains(x2 + " " + y2) || set.size() != 4) return false;
        
        return area == (x2-x1) * (y2-y1);
    }

 



Python 3 Perfect Rectangle LeetCode Solution


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class Solution:
    def isRectangleCover(self, rectangles: List[List[int]]) -> bool:
        
        area = 0
        corners = set()
        a = lambda: (Y-y) * (X-x)
        
        for x, y, X, Y in rectangles:
            area += a()
            corners ^= {(x,y), (x,Y), (X,y), (X,Y)}

        if len(corners) != 4: return False
        x, y = min(corners, key=lambda x: x[0] + x[1])
        X, Y = max(corners, key=lambda x: x[0] + x[1])
        return a() == area



 

Array-1180
String-562
Hash Table-412
Dynamic Programming-390
Math-368
Sorting-264


Greedy-257
Depth-First Search-256
Database-215
Breadth-First Search-200
Tree-195


Binary Search-191
Matrix-176
Binary Tree-160
Two Pointers-151
Bit Manipulation-140


Stack-133
Heap (Priority Queue)-117
Design-116
Graph-108
Simulation-103
Prefix Sum-96


Backtracking-92
Counting-86
Sliding Window-73
Linked List-69
Union Find-66


Ordered Set-48
Monotonic Stack-47
Recursion-43
Trie-41
Binary Search Tree-40
Divide and Conquer-40


Enumeration-39
Bitmask-37
Queue-33
Memoization-32
Topological Sort-31


Geometry-30
Segment Tree-27
Game Theory-24
Hash Function-24
Binary Indexed Tree-21


Interactive-18
Data Stream-17
String Matching-17
Rolling Hash-17
Shortest Path-16


Number Theory-16
Combinatorics-15
Randomized-12
Monotonic Queue-9
Iterator-9
Merge Sort-9


Concurrency-9
Doubly-Linked List-8
Brainteaser-8
Probability and Statistics-7
Quickselect-7


Bucket Sort-6
Suffix Array-6
Minimum Spanning Tree-5
Counting Sort-5
Shell-4


Line Sweep-4
Reservoir Sampling-4
Eulerian Circuit-3
Radix Sort-3


Strongly Connected Componen-t2
Rejection Sampling-2
Biconnected Component-1

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