Plus Minus – HackerRank Solution Java , Python 3, Python 2 , C , C++, Best and Optimal Solutions , All you need.
Solutions of Algorithms Data Structures Hard HackerRank:
Here are all the Solutions of Hard , Advanced , Expert Algorithms of Data Structure of Hacker Rank , Leave a comment for similar posts
C++ Plus Minus HackerRank Solution
#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
int main() {
int N, n, total;
float pos = 0., neg = 0., zer = 0.;
cin >> N;
total = N;
while (N--) {
cin >> n;
if (n > 0) pos++;
else if (n < 0) neg++;
else zer++;
}
cout << pos / total << endl;
cout << neg / total << endl;
cout << zer / total << endl;
return 0;
}
Java Plus Minus HackerRank Solution
import java.text.DecimalFormat;
import java.util.Scanner;
public class Solution {
public static void main(String args[])
{
Scanner scan = new Scanner(System.in);
int N=Integer.parseInt(scan.nextLine());
int arr[]= new int[N];
for(int i=0;i<N;i++)
{
arr[i]=scan.nextInt();
}
scan.close();
double pos=0;
double neg=0;
double zero=0;
for(int i=0;i<N;i++)
{
if(arr[i]>0)
{
pos=pos+1;
}
else if(arr[i]<0)
{
neg=neg+1;
}
else
{
zero=zero+1;
}
}
DecimalFormat df= new DecimalFormat("#.000");
System.out.println(df.format(pos/N));
System.out.println(df.format(neg/N));
System.out.println(df.format(zero/N));
}
}
Python 3 Plus Minus HackerRank Solution
#!/bin/python3
import math
import os
import random
import re
import sys
# Complete the plusMinus function below.
def plusMinus(arr):
x,z,y=0,0,0
for i in range(0,len(arr)):
if arr[i]>0:
x = x + 1
elif arr[i]<0:
y = y + 1
else:
z = z + 1
print(x/len(arr))
print(y/len(arr))
print(z/len(arr))
if __name__ == '__main__':
n = int(input())
arr = list(map(int, input().rstrip().split()))
plusMinus(arr)
JavaScript Plus Minus HackerRank Solution
function processData(input) {
//Enter your code here
input = input.split("\n");
var n = input.shift();
input = input.shift().split(' ');
var len = input.length;
var neg = 0.0;
var zero = 0.0;
var pos = 0.0;
input.forEach(function (num) {
num = parseInt(num);
if (num < 0) { neg++ }
else if (num > 0) { pos++ }
else { zero++ }
});
console.log((pos / len).toPrecision(3));
console.log((neg / len).toPrecision(3));
console.log((zero / len).toPrecision(3));
}
process.stdin.resume();
process.stdin.setEncoding("ascii");
_input = "";
process.stdin.on("data", function (input) {
_input += input;
});
process.stdin.on("end", function () {
processData(_input);
});
C Plus Minus HackerRank Solution
#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
int main() {
int N,A[100],iTemp;
float minus = 0,zeros = 0,plus = 0;
scanf("%d",&N);
for(iTemp=0;iTemp<N;iTemp++)
{
scanf("%d",&A[iTemp]);
if(A[iTemp] > 0)
{
plus++;
}
else if(A[iTemp] == 0)
{
zeros++;
}
else
{
minus++;
}
}
printf("%.3f\n%.3f\n%.3f\n",plus/N,minus/N, zeros/N);
/* Enter your code here. Read input from STDIN. Print output to STDOUT */
return 0;
}
Leave a comment below
