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Home Code Solutions Hackerrank Algorithms

Plus Minus – HackerRank Solution

Plus Minus - HackerRank Solution Java , Python 3, Python 2 , C , C++, Best and Optimal Solutions , All you need.

bhautik bhalala by bhautik bhalala
May 25, 2022
Reading Time: 1 min read
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15 Days to learn SQL Hard SQL(Advanced)-Solution

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Table of Contents

  • Plus Minus – HackerRank Solution Java , Python 3, Python 2 , C , C++, Best and Optimal Solutions , All you need.
  • Solutions of Algorithms Data Structures Hard HackerRank:
    • Here are all the Solutions of Hard , Advanced , Expert Algorithms of Data Structure of Hacker Rank , Leave a comment for similar posts
  • C++ Plus Minus HackerRank Solution
  • Java Plus Minus HackerRank Solution
  • Python 3 Plus Minus HackerRank Solution
  • JavaScript Plus Minus HackerRank Solution
  • C Plus Minus HackerRank Solution
    • Leave a comment below
      • Related posts:

Plus Minus – HackerRank Solution Java , Python 3, Python 2 , C , C++, Best and Optimal Solutions , All you need.

Solutions of Algorithms Data Structures Hard HackerRank:

Here are all the Solutions of Hard , Advanced , Expert Algorithms of Data Structure of Hacker Rank , Leave a comment for similar posts

C++ Plus Minus HackerRank Solution


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#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;


int main() {
    int N, n, total;
    float pos = 0., neg = 0., zer = 0.;
    
    cin >> N;
    
    total = N;
    
    while (N--) {
        cin >> n;
        if (n > 0) pos++;
        else if (n < 0) neg++;
        else zer++;
    }
    
    cout << pos / total << endl;
    cout << neg / total << endl;
    cout << zer / total << endl;
    
    return 0;
}


Java Plus Minus HackerRank Solution


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import java.text.DecimalFormat;
import java.util.Scanner;


public class Solution {
	public static void main(String args[])
	{
		Scanner scan = new Scanner(System.in);
		int N=Integer.parseInt(scan.nextLine());
		int arr[]= new int[N];
		for(int i=0;i<N;i++)
		{
			arr[i]=scan.nextInt();
		}
		scan.close();
		double pos=0;
		double neg=0;
		double zero=0;
		for(int i=0;i<N;i++)
		{
			if(arr[i]>0)
			{
				pos=pos+1;
			}
			else if(arr[i]<0)
			{
				neg=neg+1;
			}
			else
			{
				zero=zero+1;
			}
		}
		DecimalFormat df= new DecimalFormat("#.000");
		System.out.println(df.format(pos/N));
		System.out.println(df.format(neg/N));
		System.out.println(df.format(zero/N));
	}

}

 


Python 3 Plus Minus HackerRank Solution


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#!/bin/python3

import math
import os
import random
import re
import sys

# Complete the plusMinus function below.
def plusMinus(arr):
    x,z,y=0,0,0
    for i in range(0,len(arr)):
        if arr[i]>0:
            x = x + 1
        elif arr[i]<0:
            y = y + 1
        else:
            z = z + 1
    print(x/len(arr))
    print(y/len(arr))
    print(z/len(arr))

if __name__ == '__main__':
    n = int(input())

    arr = list(map(int, input().rstrip().split()))

    plusMinus(arr)


JavaScript Plus Minus HackerRank Solution


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function processData(input) {
    //Enter your code here
    input = input.split("\n");
    var n = input.shift();
    input = input.shift().split(' ');
    var len = input.length;
    
    var neg = 0.0;
    var zero = 0.0;
    var pos = 0.0;
    
    input.forEach(function (num) {
        num = parseInt(num);
        if (num < 0) { neg++ }
        else if (num > 0) { pos++ }
        else { zero++ }
    });

    console.log((pos / len).toPrecision(3));
    console.log((neg / len).toPrecision(3));
    console.log((zero / len).toPrecision(3));
} 

process.stdin.resume();
process.stdin.setEncoding("ascii");
_input = "";
process.stdin.on("data", function (input) {
    _input += input;
});

process.stdin.on("end", function () {
   processData(_input);
});


C Plus Minus HackerRank Solution


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#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int main() {
    int N,A[100],iTemp;
    float minus = 0,zeros = 0,plus = 0;
    scanf("%d",&N);
    for(iTemp=0;iTemp<N;iTemp++)
    {
        scanf("%d",&A[iTemp]);
        if(A[iTemp] > 0)
        {
            plus++;    
        }
        else if(A[iTemp] == 0)
        {
            zeros++;    
        }
        else
        {
            minus++;    
        }
        
    }
    printf("%.3f\n%.3f\n%.3f\n",plus/N,minus/N, zeros/N);
    /* Enter your code here. Read input from STDIN. Print output to STDOUT */    
    return 0;
}

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Tags: Cc++14full solutionGoHackerRank Solutionjavajava 15java 7java 8java8javascriptPlus Minuspypy 3Python 2python 3
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