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Home Code Solutions

Plus One – LeetCode Solution

Plus One - LeetCode Solution Java , Python 3, Python 2 , C , C++, Best and Optimal Solutions , All you need.

BhautikBhalala by BhautikBhalala
September 3, 2022
Reading Time: 2 mins read
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Leetcode All Problems Solutions

Leetcode All Problems Solutions

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Table of Contents

  • Plus One – LeetCode Solution Java , Python 3, Python 2 , C , C++, Best and Optimal Solutions , All you need.
  • C++ Plus One LeetCode Solution
  • Java Plus One LeetCode Solution
  • Python 3 Plus One LeetCode Solution
    • Leave a comment below
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Plus One – LeetCode Solution Java , Python 3, Python 2 , C , C++, Best and Optimal Solutions , All you need.

You are given a large integer represented as an integer array digits, where each digits[i] is the ith digit of the integer. The digits are ordered from most significant to least significant in left-to-right order. The large integer does not contain any leading 0‘s.

Increment the large integer by one and return the resulting array of digits.

 

Example 1:

Input: digits = [1,2,3]
Output: [1,2,4]
Explanation: The array represents the integer 123.
Incrementing by one gives 123 + 1 = 124.
Thus, the result should be [1,2,4].

Example 2:

Input: digits = [4,3,2,1]
Output: [4,3,2,2]
Explanation: The array represents the integer 4321.
Incrementing by one gives 4321 + 1 = 4322.
Thus, the result should be [4,3,2,2].

Example 3:

Input: digits = [9]
Output: [1,0]
Explanation: The array represents the integer 9.
Incrementing by one gives 9 + 1 = 10.
Thus, the result should be [1,0].

 

Constraints:

  • 1 <= digits.length <= 100
  • 0 <= digits[i] <= 9
  • digits does not contain any leading 0‘s.

C++ Plus One LeetCode Solution


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class Solution {
public:
    vector<int> plusOne(vector<int>& digits) {
      int n = digits.size() - 1;
      
      for (int i = n; i >= 0; --i) { // traverse digits from the last element (least significant)
        // since we begin with the last digit, increasing that digit by one
        // results in overflow.  Therefore, all elements PRIOR to digits[0]
        // need to be considered since there may be additional nines between
        // digits[0], ... , digits[n].
        if (digits[i] == 9) {  
          digits[i] = 0;
        } else {  // current digit is not 9 so we can safely increment by one
          digits[i] += 1;
          return digits;
        }
      }
      // if the program runs to this point, each 9 is now a 0.
      // to get a correct solution, we need to add one more element with 
      // a value of zero AND set digits[0] to 1 (in the most significant position)
      // to account for the carry digit.
      digits.push_back(0);
      digits[0] = 1;
      return digits;
    }
};

Java Plus One LeetCode Solution


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public int[] plusOne(int[] digits) {
        
    int n = digits.length;
    for(int i=n-1; i>=0; i--) {
        if(digits[i] < 9) {
            digits[i]++;
            return digits;
        }
        
        digits[i] = 0;
    }
    
    int[] newNumber = new int [n+1];
    newNumber[0] = 1;
    
    return newNumber;
}

 



Python 3 Plus One LeetCode Solution


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def plusOne(digits):
    num = 0
    for i in range(len(digits)):
    	num += digits[i] * pow(10, (len(digits)-1-i))
    return [int(i) for i in str(num+1)]



 

Array-1180
String-562
Hash Table-412
Dynamic Programming-390
Math-368
Sorting-264
Greedy-257
Depth-First Search-256
Database-215
Breadth-First Search-200
Tree-195
Binary Search-191
Matrix-176
Binary Tree-160
Two Pointers-151
Bit Manipulation-140
Stack-133
Heap (Priority Queue)-117
Design-116
Graph-108
Simulation-103
Prefix Sum-96
Backtracking-92
Counting-86
Sliding Window-73
Linked List-69
Union Find-66
Ordered Set-48
Monotonic Stack-47
Recursion-43
Trie-41
Binary Search Tree-40
Divide and Conquer-40
Enumeration-39
Bitmask-37
Queue-33
Memoization-32
Topological Sort-31
Geometry-30
Segment Tree-27
Game Theory-24
Hash Function-24
Binary Indexed Tree-21
Interactive-18
Data Stream-17
String Matching-17
Rolling Hash-17
Shortest Path-16
Number Theory-16
Combinatorics-15
Randomized-12
Monotonic Queue-9
Iterator-9
Merge Sort-9
Concurrency-9
Doubly-Linked List-8
Brainteaser-8
Probability and Statistics-7
Quickselect-7
Bucket Sort-6
Suffix Array-6
Minimum Spanning Tree-5
Counting Sort-5
Shell-4
Line Sweep-4
Reservoir Sampling-4
Eulerian Circuit-3
Radix Sort-3
Strongly Connected Componen-t2
Rejection Sampling-2
Biconnected Component-1

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