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Home Code Solutions Hackerrank Algorithms

Quadrant Queries – HackerRank Solution

Quadrant Queries - HackerRank Solution Java , Python 3, Python 2 , C , C++, Best and Optimal Solutions , All you need.

bhautik bhalala by bhautik bhalala
May 27, 2022
Reading Time: 1 min read
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Table of Contents

  • Quadrant Queries – HackerRank Solution Java , Python 3, Python 2 , C , C++, Best and Optimal Solutions , All you need.
  • Solutions of Algorithms Data Structures Hard HackerRank:
    • Here are all the Solutions of Hard , Advanced , Expert Algorithms of Data Structure of Hacker Rank , Leave a comment for similar posts
  • C++ Quadrant Queries HackerRank Solution
  • Java Quadrant Queries HackerRank Solution
  • Python 2 Quadrant Queries HackerRank Solution
  • C Quadrant Queries HackerRank Solution
    • Leave a comment below
      • Related posts:

Quadrant Queries – HackerRank Solution Java , Python 3, Python 2 , C , C++, Best and Optimal Solutions , All you need.

Solutions of Algorithms Data Structures Hard HackerRank:

Here are all the Solutions of Hard , Advanced , Expert Algorithms of Data Structure of Hacker Rank , Leave a comment for similar posts

C++ Quadrant Queries HackerRank Solution


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/* Enter your code here. Read input from STDIN. Print output to STDOUT */
#include <iostream>
#include <memory.h>


const int maxn = 65536*2;

struct st_node{
	int total[4];
	bool x,y;
	
};

static st_node nodes[maxn*2-1];
int n;

int tree_insert(int node, int l, int r, int index, int* total){
	for (int i=0; i<4; i++)
		nodes[node].total[i] += total[i];
	if (l<r){
		int mid = (l+r)/2;
		if (index<=mid)
			tree_insert(node*2+1, l, mid, index, total);
		else 
			tree_insert(node*2+2, mid+1, r, index, total);
	}
}

int read_point(){
	memset(nodes, 0, sizeof(nodes));
	std::cin>>n;
	for (int i=1; i<=n; i++){
		int x,y;
		int total[4];
		memset(total, 0, sizeof(total));
		std::cin>>x>>y;
		if (x==0 && y==0)
			continue;
		if (x>0 && y>0)
			total[0] = 1;
		if (x<0 && y>0)
			total[1] = 1;
		if (x<0 && y<0)
			total[2] = 1;
		if (x>0 && y<0)
			total[3] = 1;
		tree_insert(0,1,n,i,total);
	}			
}

void swap(int &x, int&y){
	x = x^y;
	y = x^y;
	x = x^y;	
}

void reflect(int *total, bool xreflect, bool yreflect){
	if (xreflect){
		swap(total[0],total[3]);
		swap(total[1],total[2]);			
	}
	if (yreflect){
		swap(total[0],total[1]);
		swap(total[2],total[3]);
	}			
}

int tree_count(int node, int l, int r, int x, int y, int* total, bool xreflect, bool yreflect){

	xreflect ^= nodes[node].x;
	yreflect ^= nodes[node].y;

	if (x<=l && r<=y){
		int tmp[4];		
		for (int i=0; i<4; i++)
			tmp[i] = nodes[node].total[i];
		reflect(tmp, xreflect, yreflect);
		for (int i=0; i<4; i++)
			total[i] += tmp[i];
		return 0;
	} 

	if (l<r){
		int mid = (l+r)/2;
		if (x<=mid)
			tree_count(node*2+1, l, mid, x, y, total, xreflect, yreflect);
		if (y>=mid+1)
			tree_count(node*2+2, mid+1, r, x, y, total, xreflect, yreflect);
	}
}

int tree_reflect(int node, int l, int r, int x, int y, bool xreflect, bool yreflect){
	if (x<=l && r<=y){
		nodes[node].x ^= xreflect;
		nodes[node].y ^= yreflect;
		return 0;
	}
	if (l<r){
		int mid=(l+r)/2;
		if (x<=mid)
			tree_reflect(node*2+1, l, mid, x, y, xreflect, yreflect);
		if (y>=mid+1)
			tree_reflect(node*2+2, mid+1, r, x, y, xreflect, yreflect);
		int ltotal[4], rtotal[4];				
		for (int i=0; i<4; i++){
			ltotal[i] = nodes[node*2+1].total[i];
			rtotal[i] = nodes[node*2+2].total[i];		
		}
		reflect(ltotal, nodes[node*2+1].x, nodes[node*2+1].y);
		reflect(rtotal, nodes[node*2+2].x, nodes[node*2+2].y);
		for (int i=0; i<4; i++)
			nodes[node].total[i] = ltotal[i]+rtotal[i];
	}	
}

int solve(){
	int q; 
	std::cin>>q;
	for (int i=0; i<q; i++){
		char type;
		int x, y;
		std::cin>>type>>x>>y;
		if (type=='C'){
			int total[4];
			memset(total, 0, sizeof(total));
			tree_count(0, 1, n, x, y, total, false, false);
			std::cout<<total[0]<<" "<<total[1]<<" "<<total[2]<<" "<<total[3]<<std::endl;			
		}		
		else if (type=='X'){
			tree_reflect(0, 1, n, x, y, true, false);			
		} 
		else if (type=='Y'){
			tree_reflect(0, 1, n, x, y, false, true);
			
		}		
	}
}

int main(){
	read_point();
	solve();
}

Java Quadrant Queries HackerRank Solution


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/* Enter your code here. Read input from STDIN. Print output to STDOUT */


import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.Arrays;

public class Solution {
	private static final int[] BC = new int[1<<16];
	public static void main(String[] argv) throws Exception {
		prep();
		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
		String line1 = br.readLine();
		int N = Integer.parseInt(line1);
		ArrayList<String> dump = new ArrayList<String>(100000);
		int[] x = new int[N/32+1];
		int[] y = new int[N/32+1];
		long rs = System.currentTimeMillis();
		for(int i=0;i<N;i++){
			String line2 = br.readLine();
			String[] tmp2 = line2.split(" ");
			if(tmp2[0].charAt(0) != '-') x[i/32] |= 1<< i%32;
			if(tmp2[1].charAt(0) != '-') y[i/32] |= 1<< i%32;
		}
		long re = System.currentTimeMillis();
		String line3 = br.readLine();
		int Q = Integer.parseInt(line3);
		boolean wasC = false;
		int[] tmp1 = new int[N/32+1];
		int[] tmp24= new int[N/32+1];
		int[] tmp2 = new int[N/32+1];
		int[] cnt1 = new int[N/32+1];
		int[] cnt24= new int[N/32+1];
		int[] cnt2 = new int[N/32+1];
		long ws = System.currentTimeMillis();
		for(int i=0;i<Q;i++){
			String line4 = br.readLine();
			String[] tmp4 = line4.split(" ");
			int sindex = Integer.parseInt(tmp4[1]);
			int eindex = Integer.parseInt(tmp4[2]);
			int sm = (sindex-1)%32;
			int sn = (sindex-1)/32;
			int em = eindex%32;
			int en = eindex/32;
			int es = eindex-sindex+1;
			if(tmp4[0].equals("X")) {
				if(sn == en){
					int mask = ((1<<(es))-1)<<(sm);
					y[en] ^= mask;
				}else{
					int mask = -1;
					int fmask = mask<<(sm);
					int emask = (1<<(em))-1;
					y[sn] ^= fmask;
					for(int j=sn+1;j<en;j++) y[j] ^= mask;
					y[en] ^= emask;
				}
				wasC = false;
			}else if(tmp4[0].equals("Y")) {
				if(sn == en){
					int mask = ((1<<(es))-1)<<(sm);
					x[en] ^= mask;
				}else{
					int mask = -1;
					int fmask = mask<<(sm);
					int emask = (1<<(em))-1;
					x[sn] ^= fmask;
					for(int j=sn+1;j<en;j++) x[j] ^= mask;
					x[en] ^= emask;
				}
				wasC = false;
			}else{
				/*
				if(!wasC || wasC){
					for(int j=0;j<x.length;j++) {
						tmp1[j]  = x[j] & y[j];
						tmp24[j] = x[j] ^ y[j];
						tmp2[j]  = tmp24[j] & y[j];
						cnt1[j] = bitCount(tmp1[j]);
						cnt24[j]= bitCount(tmp24[j]);
						cnt2[j] = bitCount(tmp2[j]);
					}
				}
				*/
				int maskes = ((1<<(es))-1)<<(sm);
				int maskall = -1;
				int fmask = maskall<<(sm);
				int emask = (1<<(em))-1;
				// 1st quadrant x bit: 1, y bit: 1 (x & y)
				int c1 = 0;
				if(sn == en){
					c1 += bitCount(x[en] & y[en] & maskes);
				}else{
					c1 += bitCount(x[sn] & y[sn] & fmask);
					for(int j=sn+1;j<en;j++) c1 += bitCount(x[j] & y[j]);
					c1 += bitCount(x[en] & y[en] & emask);
				}
				// 2nd quadrant x bit: 0, y bit: 1
				// 4th quadrant x bit: 1, y bit: 0
				// x xor y = c2 + c4
				// (x xor y) & y = c2
				int c24 = 0;
				int c2 = 0;
				if(sn == en){
					int t2 = (x[en] ^ y[en]) & maskes;
					c24 += bitCount(t2);
					c2 += bitCount(t2 & y[en]);
				}else{
					int t2 = (x[sn] ^ y[sn]) & fmask;
					c24 += bitCount(t2);
					c2 += bitCount(t2 & y[sn]);
					for(int j=sn+1;j<en;j++) {
						t2 = x[j] ^ y[j];
						c24 += bitCount(t2);
						c2 += bitCount(t2 & y[j]);
					}
					t2 = (x[en] ^ y[en]) & emask;
					c24 += bitCount(t2);
					c2 += bitCount(t2 & y[en]);
				}
				int c4 = c24 - c2;
				// 3rd quadrant x bit: 0, y bit: 0 (total - c1 - c2 - c4)
				int c3 = eindex - sindex + 1 - c1 - c2 - c4;
				dump.add(c1+" "+c2+" "+c3+" "+c4);
				//System.out.println(c1+" "+c2+" "+c3+" "+c4);
				wasC = true;
			}
		}
		long we = System.currentTimeMillis();
		for(int i=0;i<dump.size();i++) System.out.println(dump.get(i));
		br.close();
		//System.out.println("R:"+(re-rs));
		//System.out.println("W:"+(we-ws));
	}
	private static void prep() {
		int max = 1<<16;
		int step1 = 1<<8;
		for(int i=0;i<step1;i++) BC[i] = Integer.bitCount(i);
		for(int i=step1;i<max;i++){
			BC[i] = BC[i&0xFF] + BC[(i>>8)&0xFF];
		}
	}
	
	private static int bitCount(int i){
		return BC[i&0xFFFF] + BC[(i>>16)&0xFFFF];
	}
}

 




Python 2 Quadrant Queries HackerRank Solution


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/* Enter your code here. Read input from STDIN. Print output to STDOUT */
#include <iostream>
#include <memory.h>


const int maxn = 65536*2;

struct st_node{
	int total[4];
	bool x,y;
	
};

static st_node nodes[maxn*2-1];
int n;

int tree_insert(int node, int l, int r, int index, int* total){
	for (int i=0; i<4; i++)
		nodes[node].total[i] += total[i];
	if (l<r){
		int mid = (l+r)/2;
		if (index<=mid)
			tree_insert(node*2+1, l, mid, index, total);
		else 
			tree_insert(node*2+2, mid+1, r, index, total);
	}
}

int read_point(){
	memset(nodes, 0, sizeof(nodes));
	std::cin>>n;
	for (int i=1; i<=n; i++){
		int x,y;
		int total[4];
		memset(total, 0, sizeof(total));
		std::cin>>x>>y;
		if (x==0 && y==0)
			continue;
		if (x>0 && y>0)
			total[0] = 1;
		if (x<0 && y>0)
			total[1] = 1;
		if (x<0 && y<0)
			total[2] = 1;
		if (x>0 && y<0)
			total[3] = 1;
		tree_insert(0,1,n,i,total);
	}			
}

void swap(int &x, int&y){
	x = x^y;
	y = x^y;
	x = x^y;	
}

void reflect(int *total, bool xreflect, bool yreflect){
	if (xreflect){
		swap(total[0],total[3]);
		swap(total[1],total[2]);			
	}
	if (yreflect){
		swap(total[0],total[1]);
		swap(total[2],total[3]);
	}			
}

int tree_count(int node, int l, int r, int x, int y, int* total, bool xreflect, bool yreflect){

	xreflect ^= nodes[node].x;
	yreflect ^= nodes[node].y;

	if (x<=l && r<=y){
		int tmp[4];		
		for (int i=0; i<4; i++)
			tmp[i] = nodes[node].total[i];
		reflect(tmp, xreflect, yreflect);
		for (int i=0; i<4; i++)
			total[i] += tmp[i];
		return 0;
	} 

	if (l<r){
		int mid = (l+r)/2;
		if (x<=mid)
			tree_count(node*2+1, l, mid, x, y, total, xreflect, yreflect);
		if (y>=mid+1)
			tree_count(node*2+2, mid+1, r, x, y, total, xreflect, yreflect);
	}
}

int tree_reflect(int node, int l, int r, int x, int y, bool xreflect, bool yreflect){
	if (x<=l && r<=y){
		nodes[node].x ^= xreflect;
		nodes[node].y ^= yreflect;
		return 0;
	}
	if (l<r){
		int mid=(l+r)/2;
		if (x<=mid)
			tree_reflect(node*2+1, l, mid, x, y, xreflect, yreflect);
		if (y>=mid+1)
			tree_reflect(node*2+2, mid+1, r, x, y, xreflect, yreflect);
		int ltotal[4], rtotal[4];				
		for (int i=0; i<4; i++){
			ltotal[i] = nodes[node*2+1].total[i];
			rtotal[i] = nodes[node*2+2].total[i];		
		}
		reflect(ltotal, nodes[node*2+1].x, nodes[node*2+1].y);
		reflect(rtotal, nodes[node*2+2].x, nodes[node*2+2].y);
		for (int i=0; i<4; i++)
			nodes[node].total[i] = ltotal[i]+rtotal[i];
	}	
}

int solve(){
	int q; 
	std::cin>>q;
	for (int i=0; i<q; i++){
		char type;
		int x, y;
		std::cin>>type>>x>>y;
		if (type=='C'){
			int total[4];
			memset(total, 0, sizeof(total));
			tree_count(0, 1, n, x, y, total, false, false);
			std::cout<<total[0]<<" "<<total[1]<<" "<<total[2]<<" "<<total[3]<<std::endl;			
		}		
		else if (type=='X'){
			tree_reflect(0, 1, n, x, y, true, false);			
		} 
		else if (type=='Y'){
			tree_reflect(0, 1, n, x, y, false, true);
			
		}		
	}
}

int main(){
	read_point();
	solve();
}



C Quadrant Queries HackerRank Solution


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#include <assert.h>
#include <stdint.h>
#include <stdio.h>
#include <stdlib.h>

enum {
  XAXIS = 0,
  YAXIS = 1
};

/*
 * Binary tree.
 * Nodes at level k summarize a subtree of size 2^k.
 * The level and range is implicit.
 */

typedef struct node node;
struct node {
  int count;
  node *left, *right;
};

node *pool;
int nnodes, npool;

typedef struct tree tree;
struct tree {
  node *root[4];
  int nlevels;
};

node *newnode() {
  assert(nnodes < npool);
  return &pool[nnodes++];
}

node *mktree(int level) {
  node *np;

  np = newnode();
  if (level == 0)
    return np;

  np->left = mktree(level-1);
  np->right = mktree(level-1);
  return np;
}

tree *inittree(int n) {
  tree *tp;
  int i;

  tp = (tree *) malloc(sizeof(*tp));
  if (tp == NULL)
    exit(1);
  
  tp->nlevels = 0;
  while ((1 << tp->nlevels) < n)
    tp->nlevels++;

  npool = 4 * (1 << (tp->nlevels+1));
  pool = calloc(npool, sizeof(node));
  if (pool == NULL)
    exit(1);

  for (i = 0; i < 4; i++)
    tp->root[i] = mktree(tp->nlevels);

  return tp;
}

void _add(node *np, int lvl, int idx, int x) {
  int lt, rt, mid;

  np->count++;

  if (lvl == 0)
    return;

  lt = (1<<lvl) * idx;
  mid = lt + (1<<(lvl-1));
  rt = lt + (1<<lvl) - 1;

  assert(lt <= x && x <= rt);
  if (x < mid)
    _add(np->left, lvl-1, 2*idx, x);
  else
    _add(np->right, lvl-1, 2*idx + 1, x);
}

/* Add a value at x in quadrant q. */
void add(tree *tp, int x, int q) {
  _add(tp->root[q], tp->nlevels, 0, x);
}

int _count(node *np, int lvl, int idx, int l, int r) {
  int lt, rt;

  lt = (1<<lvl) * idx;
  rt = lt + (1<<lvl) - 1;

  /* Out of bounds. */
  if (r < lt) return 0;
  if (l > rt) return 0;

  /* Whole range. */
  if (l <= lt && rt <= r)
    return np->count;

  /* Left and right children. */
  return _count(np->left, lvl-1, 2*idx, l, r) +
    _count(np->right, lvl-1, 2*idx + 1, l, r);
}

/* count: print # in each quadrant from l -> r inclusive. */
void count(tree *tp, int l, int r) {
  int q[4];
  int i;

  for (i = 0; i < 4; i++)
    q[i] = _count(tp->root[i], tp->nlevels, 0, l, r);
  printf("%d %d %d %d\n", q[0], q[1], q[2], q[3]);
}

void _flip(node **np, int lvl, int idx, int l, int r, int typ) {
  int lt, rt, i;
  node *tmp, *lp[4], *rp[4];

  lt = (1<<lvl) * idx;
  rt = lt + (1<<lvl) - 1;

  /* Out of bounds. */
  if (r < lt) return;
  if (l > rt) return;

  /* Whole range. */
  if (l <= lt && rt <= r) {
    assert(typ == XAXIS || typ == YAXIS);
    switch (typ) {
    case XAXIS:
      tmp = np[0]; np[0] = np[3]; np[3] = tmp;
      tmp = np[1]; np[1] = np[2]; np[2] = tmp;
      break;
    case YAXIS:
      tmp = np[0]; np[0] = np[1]; np[1] = tmp;
      tmp = np[2]; np[2] = np[3]; np[3] = tmp;
      break;
    default:
      assert(0);
      break;
    }
    return;
  }

  assert(lvl > 0);

  /* Left and right children. */
  for (i = 0; i < 4; i++) {
    lp[i] = np[i]->left;
    rp[i] = np[i]->right;
  }

  _flip(lp, lvl-1, 2*idx, l, r, typ);
  _flip(rp, lvl-1, 2*idx + 1, l, r, typ);

  for (i = 0; i < 4; i++) {
    np[i]->left = lp[i];
    np[i]->right = rp[i];
    np[i]->count = lp[i]->count + rp[i]->count;
  }
}

/* flip: flip points about axis. */
void flip(tree *tp, int l, int r, int typ) {
  _flip(tp->root, tp->nlevels, 0, l, r, typ);
}

int quadrant(int x, int y) {
  if (x > 0 && y > 0) return 0;
  if (x < 0 && y > 0) return 1;
  if (x < 0 && y < 0) return 2;
  if (x > 0 && y < 0) return 3;
  /* shouldn't get here */
  assert(0);
  return -1;
}

int main() {
  int i, x, y, a, b, npoints, nqueries;
  char query;
  tree *tp;

  if (scanf(" %d", &npoints) != 1)
    return 1;
  tp = inittree(npoints);
  for (i = 0; i < npoints; i++) {
    if (scanf(" %d %d", &x, &y) != 2)
      return 1;
    if (x == 0 || y == 0)
      return 1;
    add(tp, i, quadrant(x, y));
  }

  if (scanf(" %d", &nqueries) != 1)
    return 1;
  for (i = 0; i < nqueries; i++) {
    if (scanf(" %c %d %d", &query, &a, &b) != 3)
      return 1;
    switch (query) {
    case 'C':
      count(tp, a-1, b-1);
      break;
    case 'X':
      flip(tp, a-1, b-1, XAXIS);
      break;
    case 'Y':
      flip(tp, a-1, b-1, YAXIS);
      break;
    default:
      return 1;
    }
  }
  
  return 0;
}

 

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Exclusive Time of Functions - LeetCode Solution Java , Python 3, Python 2 , C , C++, Best and Optimal Solutions...

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