Rotate Image – LeetCode Solution Java , Python 3, Python 2 , C , C++, Best and Optimal Solutions , All you need.
You are given an n x n 2D matrix representing an image, rotate the image by 90 degrees (clockwise).
You have to rotate the image in-place, which means you have to modify the input 2D matrix directly. DO NOT allocate another 2D matrix and do the rotation.
Example 1:
Input: matrix = [[1,2,3],[4,5,6],[7,8,9]] Output: [[7,4,1],[8,5,2],[9,6,3]]
Example 2:
Input: matrix = [[5,1,9,11],[2,4,8,10],[13,3,6,7],[15,14,12,16]] Output: [[15,13,2,5],[14,3,4,1],[12,6,8,9],[16,7,10,11]]
Constraints:
n == matrix.length == matrix[i].length1 <= n <= 20-1000 <= matrix[i][j] <= 1000
C++ Rotate Image LeetCode Solution
void rotate(vector<vector<int>>& matrix) {
int n = matrix.size();
int a = 0;
int b = n-1;
while(a<b){
for(int i=0;i<(b-a);++i){
swap(matrix[a][a+i], matrix[a+i][b]);
swap(matrix[a][a+i], matrix[b][b-i]);
swap(matrix[a][a+i], matrix[b-i][a]);
}
++a;
--b;
}
}
Java Rotate Image LeetCode Solution
public class Solution {
public void rotate(int[][] matrix) {
for(int i = 0; i<matrix.length; i++){
for(int j = i; j<matrix[0].length; j++){
int temp = 0;
temp = matrix[i][j];
matrix[i][j] = matrix[j][i];
matrix[j][i] = temp;
}
}
for(int i =0 ; i<matrix.length; i++){
for(int j = 0; j<matrix.length/2; j++){
int temp = 0;
temp = matrix[i][j];
matrix[i][j] = matrix[i][matrix.length-1-j];
matrix[i][matrix.length-1-j] = temp;
}
}
}
}
Python 3 Rotate Image LeetCode Solution
# reverse
l = 0
r = len(matrix) -1
while l < r:
matrix[l], matrix[r] = matrix[r], matrix[l]
l += 1
r -= 1
# transpose
for i in range(len(matrix)):
for j in range(i):
matrix[i][j], matrix[j][i] = matrix[j][i], matrix[i][j]
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