• Home
  • Top Posts
  • Code Solutions
  • How to
  • News
  • Trending
  • Anime
  • Health
  • Education
Friday, January 27, 2023
  • Login
Zeroplusfour
No Result
View All Result
  • Home
  • Top Posts
  • Code Solutions
  • How to
  • News
  • Trending
  • Anime
  • Health
  • Education
  • Home
  • Top Posts
  • Code Solutions
  • How to
  • News
  • Trending
  • Anime
  • Health
  • Education
No Result
View All Result
Zeroplusfour
No Result
View All Result
Home Code Solutions Hackerrank Algorithms

Savita And Friends – HackerRank Solution

Savita And Friends - HackerRank Solution Java , Python 3, Python 2 , C , C++, Best and Optimal Solutions , All you need.

bhautik bhalala by bhautik bhalala
May 26, 2022
Reading Time: 1 min read
0
15 Days to learn SQL Hard SQL(Advanced)-Solution

15 Days to learn SQL Hard SQL(Advanced)-Solution alt text

Spread the love

Table of Contents

  • Savita And Friends  – HackerRank Solution Java , Python 3, Python 2 , C , C++, Best and Optimal Solutions , All you need.
  • Solutions of Algorithms Data Structures Hard HackerRank:
    • Here are all the Solutions of Hard , Advanced , Expert Algorithms of Data Structure of Hacker Rank , Leave a comment for similar posts
  • C++ Savita And Friends  HackerRank Solution
  • Java Savita And Friends HackerRank Solution
  • Python 3 Savita And Friends HackerRank Solution
  • C Savita And Friends HackerRank Solution
    • Leave a comment below
      • Related posts:

Savita And Friends  – HackerRank Solution Java , Python 3, Python 2 , C , C++, Best and Optimal Solutions , All you need.

Solutions of Algorithms Data Structures Hard HackerRank:

Here are all the Solutions of Hard , Advanced , Expert Algorithms of Data Structure of Hacker Rank , Leave a comment for similar posts

C++ Savita And Friends  HackerRank Solution


Copy Code Copied Use a different Browser

/*
*/

//#pragma comment(linker, "/STACK:16777216")
#include <fstream>
#include <iostream>
#include <string>
#include <complex>
#include <math.h>
#include <set>
#include <vector>
#include <map>
#include <queue>
#include <stdio.h>
#include <stack>
#include <algorithm>
#include <list>
#include <ctime>
//#include <memory.h>

#define y0 sdkfaslhagaklsldk
#define y1 aasdfasdfasdf
#define yn askfhwqriuperikldjk
#define j1 assdgsdgasghsf
#define tm sdfjahlfasfh
#define lr asgasgash

#define eps 1e-14
//#define M_PI 3.141592653589793
#define bs 1000000007
#define bsize 256
//#define N 120000

using namespace std;

long tests;
vector<pair<long, long> > g[200000];
long a,b,c;
long long cp1,cp2,tt;
long n,m,k;
long long dist[200000];

long bda,bdb;
double nmove;
set<pair<long long, long > > sett;
set<pair<long long, long> > ::iterator it;
pair<long long, long> tp;
long long qv;
long long qcost;
long d1[200000],d2[200000];
double l,r,mid1,mid2;

double gett(double val)
{
 double bst=0;
 for (int i=1;i<=n;i++)
  bst=max(bst,min(d1[i]+val,d2[i]+tt-val));
  return bst;
}

int main(){
//freopen("pattern.in","r",stdin);
//freopen("pattern.out","w",stdout);
//freopen("C:/input.txt","r",stdin);
//freopen("C:/output.txt","w",stdout);
ios_base::sync_with_stdio(0);
//cin.tie(0);

cin>>tests;
for (;tests;--tests)
{
 cin>>n>>m>>k;
 for (int i=1;i<=n;i++)
  g[i].clear();
 for (int i=1;i<=m;i++)
  {
   cin>>a>>b>>c;
   if (i==k){cp1=a,cp2=b;tt=c;}
   g[a].push_back(make_pair(b,c));
   g[b].push_back(make_pair(a,c));
  }
 
 for (int i=1;i<=n;i++)
  dist[i]=1e16;
 dist[cp1]=0;
 sett.clear();
 for (int i=1;i<=n;i++)
  sett.insert(make_pair(dist[i],i));
 for (int iter=1;iter<=n;iter++)
 {
  it=sett.begin();
  tp=(*it);
  sett.erase(it);
  qv=tp.second;
  qcost=tp.first;
  for (int i=0;i<g[qv].size();i++)
  {
   long long nv=g[qv][i].first;
   long long ncost=g[qv][i].second+qcost;
   if (min(nv,qv)==min(cp1,cp2)&&max(nv,qv)==max(cp1,cp2))
    continue;
   if (dist[nv]>ncost)
   {
    sett.erase(make_pair(dist[nv],nv));
    dist[nv]=ncost;
    sett.insert(make_pair(dist[nv],nv));
   }
  }
 }
 
 for (int i=1;i<=n;i++)
  d1[i]=dist[i];
 
 // -- 2nd end
 
 for (int i=1;i<=n;i++)
  dist[i]=1e16;
 dist[cp2]=0;
 sett.clear();
 for (int i=1;i<=n;i++)
  sett.insert(make_pair(dist[i],i));
 for (int iter=1;iter<=n;iter++)
 {
  it=sett.begin();
  tp=(*it);
  sett.erase(it);
  qv=tp.second;
  qcost=tp.first;
  for (int i=0;i<g[qv].size();i++)
  {
   long long nv=g[qv][i].first;
   long long ncost=g[qv][i].second+qcost;
   if (min(nv,qv)==min(cp1,cp2)&&max(nv,qv)==max(cp1,cp2))
    continue;
   if (dist[nv]>ncost)
   {
    sett.erase(make_pair(dist[nv],nv));
    dist[nv]=ncost;
    sett.insert(make_pair(dist[nv],nv));
   }
  }
 }
 
 for (int i=1;i<=n;i++)
  d2[i]=dist[i];
 /*
 for (int i=1;i<=n;i++)
  cout<<d1[i]<<" ";
  cout<<endl;
 for (int i=1;i<=n;i++)
  cout<<d2[i]<<" ";
  cout<<endl;
   */
 l=0;
 r=tt;
 while (r-l>1e-6)
 {
  mid1=l*2+r;
  mid2=l+r*2;
  mid1/=3;
  mid2/=3;
  if (gett(mid1)<gett(mid2))r=mid2;
  else l=mid1;
 }
 if (gett(0)<gett(l))l=0;
 if (gett(tt)<gett(l))l=tt;
// cout<<gett(2)<<endl;
 cout.precision(5);
 cout<<fixed<<l<<" "<<gett(l)<<endl;
}

cin.get();cin.get();
return 0;}

Java Savita And Friends HackerRank Solution


Copy Code Copied Use a different Browser

import java.io.*;
import java.util.*;

public class Solution {

    static final long INF = 1000000000000000000L;

    static class Edge {
        int o;
        long len;

        public Edge(int o, long len) {
            this.o = o;
            this.len = len;
        }
    }

    static class Point implements Comparable<Point> {
        long x, y;

        public Point(long x, long y) {
            this.x = x;
            this.y = y;
        }

        @Override
        public int compareTo(Point o) {
            if (x == o.x) {
                return Long.compare(o.y, y);
            }
            return Long.compare(x, o.x);
        }
    }

    public static void solve(Input in, PrintWriter out) throws IOException {
        int tests = in.nextInt();
        for (int test = 0; test < tests; ++test) {
            int n = in.nextInt();
            int m = in.nextInt();
            int k = in.nextInt() - 1;
            ArrayList<Edge>[] edges = new ArrayList[n];
            for (int i = 0; i < n; ++i) {
                edges[i] = new ArrayList<Edge>();
            }
            int a0 = -1, b0 = -1;
            long c0 = -1;
            for (int i = 0; i < m; ++i) {
                int a = in.nextInt() - 1;
                int b = in.nextInt() - 1;
                long c = in.nextLong();
                if (i == k) {
                    a0 = a;
                    b0 = b;
                    c0 = c;
                } else {
                    edges[a].add(new Edge(b, c));
                    edges[b].add(new Edge(a, c));
                }
            }
            long[] da = dists(a0, edges);
            long[] db = dists(b0, edges);
            Point[] points = new Point[n];
            for (int i = 0; i < n; ++i) {
                if (da[i] == INF && db[i] == INF) {
                    throw new AssertionError();
                }
                if (da[i] + c0 < db[i]) {
                    points[i] = new Point(-da[i], da[i] + 2 * c0);
                } else if (db[i] + c0 < da[i]) {
                    points[i] = new Point(-db[i] - c0, db[i] + c0);
                } else {
                    points[i] = new Point(-da[i], db[i] + c0);
                }
            }
            Arrays.sort(points);
            Point last = null, ans = null;
            for (Point p : points) {
                Point cur;
                if (last == null) {
                    cur = new Point(0, -2 * p.x);
                } else if (last.y < p.y) {
                    cur = new Point(p.x + last.y, last.y - p.x);
                } else {
                    continue;
                }
                last = p;
                if (ans == null || ans.y > cur.y || ans.y == cur.y && ans.x > cur.x) {
                    ans = cur;
                }
            }
            if (last == null) {
                throw new AssertionError();
            }
            {
                Point cur = new Point(2 * c0, 2 * (last.y - c0));
                if (ans == null || ans.y > cur.y || ans.y == cur.y && ans.x > cur.x) {
                    ans = cur;
                }
            }
            out.printf("%.5f %.5f%n", ans.x / 2.0, ans.y / 2.0);
        }
    }

    static class Node implements Comparable<Node> {
        int i;
        long dist;

        public Node(int i, long dist) {
            this.i = i;
            this.dist = dist;
        }

        @Override
        public int compareTo(Node o) {
            return Long.compare(dist, o.dist);
        }
    }

    private static long[] dists(int v0, ArrayList<Edge>[] edges) {
        long[] d = new long[edges.length];
        Arrays.fill(d, INF);
        PriorityQueue<Node> pq = new PriorityQueue<Node>();
        d[v0] = 0;
        pq.add(new Node(v0, 0));
        while (!pq.isEmpty()) {
            Node n = pq.poll();
            if (d[n.i] != n.dist) {
                continue;
            }
            for (Edge e : edges[n.i]) {
                if (d[e.o] > n.dist + e.len) {
                    d[e.o] = n.dist + e.len;
                    pq.add(new Node(e.o, d[e.o]));
                }
            }
        }
        return d;
    }

    public static void main(String[] args) throws IOException {
        PrintWriter out = new PrintWriter(System.out);
        solve(new Input(new BufferedReader(new InputStreamReader(System.in))), out);
        out.close();
    }

    static class Input {
        BufferedReader in;
        StringBuilder sb = new StringBuilder();

        public Input(BufferedReader in) {
            this.in = in;
        }

        public Input(String s) {
            this.in = new BufferedReader(new StringReader(s));
        }

        public String next() throws IOException {
            sb.setLength(0);
            while (true) {
                int c = in.read();
                if (c == -1) {
                    return null;
                }
                if (" \n\r\t".indexOf(c) == -1) {
                    sb.append((char)c);
                    break;
                }
            }
            while (true) {
                int c = in.read();
                if (c == -1 || " \n\r\t".indexOf(c) != -1) {
                    break;
                }
                sb.append((char)c);
            }
            return sb.toString();
        }

        public int nextInt() throws IOException {
            return Integer.parseInt(next());
        }

        public long nextLong() throws IOException {
            return Long.parseLong(next());
        }

        public double nextDouble() throws IOException {
            return Double.parseDouble(next());
        }
    }
}

 



Python 3 Savita And Friends HackerRank Solution


Copy Code Copied Use a different Browser

import heapq
def calc_dist(G, start):
   dist = [-1] * len(G)
   active = [(0, start)]
   while active:
      d, i = heapq.heappop(active)
      if dist[i] >= 0: continue
      dist[i] = d
      for j, e in G[i]:
         if dist[j] < 0:
            heapq.heappush(active, (d+e, j))
   return dist

T = int(input())
for t in range(T):
   N, M, K = map(int, input().split())
   edges = []
   G = [[] for i in range(N+1)]
   for i in range(M):
      A, B, C = map(int, input().split())
      edges.append((A, B, C))
      G[A].append((B, C))
      G[B].append((A, C))
   A, B, C = edges[K-1]
   distA = calc_dist(G, A)
   distB = calc_dist(G, B)
   peaks = []
   for i in range(1,N+1):
      x = (C + distB[i] - distA[i]) / 2
      peaks.append((x, distA[i] + x))
   peaks.sort()
   pts = []
   for x, y in peaks:
      while pts:
         x0, y0 = pts[-1]
         if y0 > y - x + x0: break
         pts.pop()
      if pts:
         x0, y0 = pts[-1]
         xy = x0 + y0
         if y > xy - x:
            x1 = (xy - y + x) / 2
            pts.append((x1, xy - x1))
            pts.append((x, y))
      else:
         if x > 0:
            pts.append((0, y - x))
         pts.append((x, y))
   x, y = pts[-1]
   if x < C: pts.append((C, y + x - C))
   xmin, ymin = pts[0]
   for x, y in pts:
      if y < ymin:
         xmin = x
         ymin = y
   print("%.5f %.5f" % (xmin, ymin))




C Savita And Friends HackerRank Solution


Copy Code Copied Use a different Browser

#include <stdio.h>
#include <stdlib.h>
typedef struct{
  int u;
  long long w;
} node;
void heap_insert(node *heap,node *elem,int *size,int *heap_list);
void heap_update(node *heap,node *elem,int *heap_list);
void heap_read(node *heap,int *size,int *heap_list,node *ans);
void DJ(int N,int M,int*u,int*v,int*w,int*v_right,int*list_index,int*left_index,int*right_index,int S,long long*d);
void sort_a2(int*a,int*b,int size);
void merge2(int*a,int*left_a,int*right_a,int*b,int*left_b,int*right_b,int left_size,int right_size);
void sort_a3(int*a,int*b,int*c,int size);
void merge3(int*a,int*left_a,int*right_a,int*b,int*left_b,int*right_b,int*c,int*left_c,int*right_c,int left_size,int right_size);

int main(){
  int T,N,M,K,A,B,C,f,i;
  int *u,*v,*w,*v_right,*list_index,*left_index,*right_index;
  long long max1,max2,maxa,maxb,min;
  long long *d_a,*d_b;
  u=(int*)malloc(100000*sizeof(int));
  v=(int*)malloc(100000*sizeof(int));
  w=(int*)malloc(100000*sizeof(int));
  v_right=(int*)malloc(100000*sizeof(int));
  list_index=(int*)malloc(100000*sizeof(int));
  left_index=(int*)malloc(100000*sizeof(int));
  right_index=(int*)malloc(100000*sizeof(int));
  d_a=(long long*)malloc(100000*sizeof(long long));
  d_b=(long long*)malloc(100000*sizeof(long long));
  scanf("%d",&T);
  while(T--){
    scanf("%d%d%d",&N,&M,&K);
    for(i=0;i<M;i++){
      scanf("%d%d%d",u+i,v+i,w+i);
      u[i]--;
      v[i]--;
      list_index[i]=i;
    }
    A=u[K-1];
    B=v[K-1];
    C=w[K-1];
    for(i=0;i<N;i++)
      d_a[i]=d_b[i]=-1;
    sort_a3(u,v,w,M);
    for(i=0;i<M;i++)
      v_right[i]=v[i];
    sort_a2(v_right,list_index,M);
    for(i=0;i<M;i++){
      if(i==0 || u[i]!=u[i-1])
        left_index[u[i]]=i;
      if(i==0 || v_right[i]!=v_right[i-1])
        right_index[v_right[i]]=i;
    }
    DJ(N,M,u,v,w,v_right,list_index,left_index,right_index,A,d_a);
    DJ(N,M,u,v,w,v_right,list_index,left_index,right_index,B,d_b);
    max1=max2=maxa=maxb=-1;
    for(i=0;i<N;i++){
      if(d_a[i]>maxa)
        maxa=d_a[i];
      if(d_b[i]>maxb)
        maxb=d_b[i];
      min=(d_a[i]>d_b[i])?d_b[i]:d_a[i];
      if(min>max1){
        max1=min;
        if(min==d_a[i])
          f=0;
        else
          f=1;
      }
      else if(min==max1 && f && min==d_a[i])
        f=0;
    }
    if(f){
      for(i=0;i<N;i++){
        min=(d_a[i]>d_b[i])?d_b[i]:d_a[i];
        if(min>max2 && min!=d_b[i] && d_b[i]>max1 && d_b[i]>=(double)min+((double)C+max1-min)/2)
          max2=min;
      }
      if((max2==-1 || max1-max2>=C) && maxa>maxb)
        printf("%.5lf %.5lf\n",(double)C,(double)maxb);
      else if(maxa<=(double)max2+((double)C+max1-max2)/2)
        printf("%.5lf %.5lf\n",0.0,(double)maxa);
      else
        printf("%.5lf %.5lf\n",((double)C+max1-max2)/2,(double)max2+((double)C+max1-max2)/2);
    }
    else{
      for(i=0;i<N;i++){
        min=(d_a[i]>d_b[i])?d_b[i]:d_a[i];
        if(min>max2 && min!=d_a[i] && d_a[i]>max1 && d_a[i]>(double)max1+((double)C-max1+min)/2)
          max2=min;
      }
      if((max2==-1 || max1-max2>=C) && maxb>=maxa)
        printf("%.5lf %.5lf\n",0.0,(double)maxa);
      else if(maxb<(double)max1+((double)C-max1+max2)/2)
        printf("%.5lf %.5lf\n",(double)C,(double)maxb);
      else
        printf("%.5lf %.5lf\n",((double)C-max1+max2)/2,(double)max1+((double)C-max1+max2)/2);
    }
  }
  return 0;
}
void heap_insert(node *heap,node *elem,int *size,int *heap_list){
  (*size)++;
  int index=(*size);
  while(index>1 && elem->w<heap[index/2].w){
    heap[index]=heap[index/2];
    heap_list[heap[index].u]=index;
    index/=2;
  }
  heap[index]=(*elem);
  heap_list[elem->u]=index;
  return;
}
void heap_update(node *heap,node *elem,int *heap_list){
  int index=heap_list[elem->u];
  while(index>1 && elem->w<heap[index/2].w){
    heap[index]=heap[index/2];
    heap_list[heap[index].u]=index;
    index/=2;
  }
  heap[index]=(*elem);
  heap_list[elem->u]=index;
  return;
}
void heap_read(node *heap,int *size,int *heap_list,node *ans){
  (*ans)=heap[1];
  int index=1;
  while(index*2<*size && heap[*size].w>heap[index*2].w || index*2+1<*size && heap[*size].w>heap[index*2+1].w){
    index=(heap[index*2].w>heap[index*2+1].w)?index*2+1:index*2;
    heap[index/2]=heap[index];
    heap_list[heap[index].u]=index/2;
  }
  heap[index]=heap[*size];
  heap_list[heap[index].u]=index;
  (*size)--;
  return;
}
void DJ(int N,int M,int*u,int*v,int*w,int*v_right,int*list_index,int*left_index,int*right_index,int S,long long*d){
  int i,next_solve,heap_size=0,*heap_list;
  node elem,*heap;
  heap=(node*)malloc(N*sizeof(node));
  heap_list=(int*)malloc(N*sizeof(int));
  d[S]=0;
  next_solve=S;
  while(1){
    for(i=left_index[next_solve];i>=0 && i<M && u[i]==next_solve;i++)
      if(d[v[i]]==-1 || d[v[i]]>d[next_solve]+w[i]){
        elem.u=v[i];
        elem.w=d[next_solve]+w[i];
        if(d[v[i]]==-1)
          heap_insert(heap,&elem,&heap_size,heap_list);
        else
          heap_update(heap,&elem,heap_list);
        d[v[i]]=d[next_solve]+w[i];
      }
    for(i=right_index[next_solve];i>=0 && i<M && v_right[i]==next_solve;i++)
      if(d[u[list_index[i]]]==-1 || d[u[list_index[i]]]>d[next_solve]+w[list_index[i]]){
        elem.u=u[list_index[i]];
        elem.w=d[next_solve]+w[list_index[i]];
        if(d[u[list_index[i]]]==-1)
          heap_insert(heap,&elem,&heap_size,heap_list);
        else
          heap_update(heap,&elem,heap_list);
        d[u[list_index[i]]]=d[next_solve]+w[list_index[i]];
      }
    if(heap_size==0)
      break;
    heap_read(heap,&heap_size,heap_list,&elem);
    next_solve=elem.u;
  }
  free(heap);
  free(heap_list);
  return;
}
void sort_a2(int*a,int*b,int size){
  if (size < 2)
    return;
  int m = (size+1)/2,i;
  int*left_a,*left_b,*right_a,*right_b;
  left_a=(int*)malloc(m*sizeof(int));
  right_a=(int*)malloc((size-m)*sizeof(int));
  left_b=(int*)malloc(m*sizeof(int));
  right_b=(int*)malloc((size-m)*sizeof(int));
  for(i=0;i<m;i++){
    left_a[i]=a[i];
    left_b[i]=b[i];
  }
  for(i=0;i<size-m;i++){
    right_a[i]=a[i+m];
    right_b[i]=b[i+m];
  }
  sort_a2(left_a,left_b,m);
  sort_a2(right_a,right_b,size-m);
  merge2(a,left_a,right_a,b,left_b,right_b,m,size-m);
  free(left_a);
  free(right_a);
  free(left_b);
  free(right_b);
  return;
}
void merge2(int*a,int*left_a,int*right_a,int*b,int*left_b,int*right_b,int left_size,int right_size){
  int i = 0, j = 0;
  while (i < left_size|| j < right_size) {
    if (i == left_size) {
      a[i+j] = right_a[j];
      b[i+j] = right_b[j];
      j++;
    } else if (j == right_size) {
      a[i+j] = left_a[i];
      b[i+j] = left_b[i];
      i++;
    } else if (left_a[i] <= right_a[j]) {
      a[i+j] = left_a[i];
      b[i+j] = left_b[i];
      i++;
    } else {
      a[i+j] = right_a[j];
      b[i+j] = right_b[j];
      j++;
    }
  }
  return;
}
void sort_a3(int*a,int*b,int*c,int size){
  if (size < 2)
    return;
  int m = (size+1)/2,i;
  int *left_a,*left_b,*left_c,*right_a,*right_b,*right_c;
  left_a=(int*)malloc(m*sizeof(int));
  right_a=(int*)malloc((size-m)*sizeof(int));
  left_b=(int*)malloc(m*sizeof(int));
  right_b=(int*)malloc((size-m)*sizeof(int));
  left_c=(int*)malloc(m*sizeof(int));
  right_c=(int*)malloc((size-m)*sizeof(int));
  for(i=0;i<m;i++){
    left_a[i]=a[i];
    left_b[i]=b[i];
    left_c[i]=c[i];
  }
  for(i=0;i<size-m;i++){
    right_a[i]=a[i+m];
    right_b[i]=b[i+m];
    right_c[i]=c[i+m];
  }
  sort_a3(left_a,left_b,left_c,m);
  sort_a3(right_a,right_b,right_c,size-m);
  merge3(a,left_a,right_a,b,left_b,right_b,c,left_c,right_c,m,size-m);
  free(left_a);
  free(right_a);
  free(left_b);
  free(right_b);
  free(left_c);
  free(right_c);
  return;
}
void merge3(int*a,int*left_a,int*right_a,int*b,int*left_b,int*right_b,int*c,int*left_c,int*right_c,int left_size,int right_size){
  int i = 0, j = 0;
  while (i < left_size|| j < right_size) {
    if (i == left_size) {
      a[i+j] = right_a[j];
      b[i+j] = right_b[j];
      c[i+j] = right_c[j];
      j++;
    } else if (j == right_size) {
      a[i+j] = left_a[i];
      b[i+j] = left_b[i];
      c[i+j] = left_c[i];
      i++;
    } else if (left_a[i] <= right_a[j]) {
      a[i+j] = left_a[i];
      b[i+j] = left_b[i];
      c[i+j] = left_c[i];
      i++;
    } else {
      a[i+j] = right_a[j];
      b[i+j] = right_b[j];
      c[i+j] = right_c[j];
      j++;
    }
  }
  return;
}

 

Leave a comment below

 

Related posts:

15 Days to learn SQL Hard SQL(Advanced)-SolutionHow Many Substrings? – HackerRank Solution 15 Days to learn SQL Hard SQL(Advanced)-SolutionTime Conversion – HackerRank Solution 15 Days to learn SQL Hard SQL(Advanced)-SolutionZig Zag Sequence – HackerRank Solution 15 Days to learn SQL Hard SQL(Advanced)-SolutionNo Prefix Set – HackerRank Solution 15 Days to learn SQL Hard SQL(Advanced)-SolutionProblem solving – HackerRank Solution 15 Days to learn SQL Hard SQL(Advanced)-SolutionRecording Episodes – HackerRank Solution
Tags: Cc++14full solutionGoHackerRank Solutionjavajava 15java 7java 8java8javascriptpypy 3Python 2python 3Savita And Friends
ShareTweetPin
bhautik bhalala

bhautik bhalala

Related Posts

Leetcode All Problems Solutions
Code Solutions

Exclusive Time of Functions – LeetCode Solution

by admin
October 5, 2022
0
29

Exclusive Time of Functions - LeetCode Solution Java , Python 3, Python 2 , C , C++, Best and Optimal Solutions...

Read more
Leetcode All Problems Solutions

Smallest Range Covering Elements from K Lists – LeetCode Solution

October 5, 2022
32
Leetcode All Problems Solutions

Course Schedule III – LeetCode Solution

October 5, 2022
25
Leetcode All Problems Solutions

Maximum Product of Three Numbers – LeetCode Solution

September 11, 2022
52
Leetcode All Problems Solutions

Task Scheduler – LeetCode Solution

September 11, 2022
119
Leetcode All Problems Solutions

Valid Triangle Number – LeetCode Solution

September 11, 2022
28
Next Post
15 Days to learn SQL Hard SQL(Advanced)-Solution

Liars - HackerRank Solution

15 Days to learn SQL Hard SQL(Advanced)-Solution

Jumping Rooks - HackerRank Solution

Leave a Reply Cancel reply

Your email address will not be published. Required fields are marked *

You may also like

15 Days to learn SQL Hard SQL(Advanced)-SolutionHow Many Substrings? – HackerRank Solution 15 Days to learn SQL Hard SQL(Advanced)-SolutionTime Conversion – HackerRank Solution 15 Days to learn SQL Hard SQL(Advanced)-SolutionZig Zag Sequence – HackerRank Solution 15 Days to learn SQL Hard SQL(Advanced)-SolutionNo Prefix Set – HackerRank Solution 15 Days to learn SQL Hard SQL(Advanced)-SolutionProblem solving – HackerRank Solution 15 Days to learn SQL Hard SQL(Advanced)-SolutionRecording Episodes – HackerRank Solution

Categories

  • Algorithms
  • Anime
  • Biography
  • Business
  • Code Solutions
  • Cosmos
  • Countdowns
  • Culture
  • Economy
  • Education
  • Entertainment
  • Finance
  • Games
  • Hackerrank
  • Health
  • How to
  • Investment
  • LeetCode
  • Lifestyle
  • LINUX SHELL
  • Manga
  • News
  • Opinion
  • Politics
  • Sports
  • SQL
  • Tech
  • Travel
  • Uncategorized
  • Updates
  • World
  • DMCA
  • Home
  • My account
  • Privacy Policy
  • Top Posts

Recent Blogs

Leetcode All Problems Solutions

Exclusive Time of Functions – LeetCode Solution

October 5, 2022
Leetcode All Problems Solutions

Smallest Range Covering Elements from K Lists – LeetCode Solution

October 5, 2022
Veranda IPO Price Size GMP Review | Learning Solutions IPO Opens Date
Finance

Veranda IPO Price Size GMP Review | Learning Solutions IPO Opens Date

May 2, 2022
9
15 Days to learn SQL Hard SQL(Advanced)-Solution
Algorithms

Demanding Money- HackerRank Solution

May 26, 2022
70
Biography

Priya Bhavani Shankar Net Worth, Age, Height , Achivements and more

September 8, 2022
0
Leetcode All Problems Solutions
Code Solutions

Task Scheduler – LeetCode Solution

September 11, 2022
119

© 2022 ZeroPlusFour - Latest News & Blog.

No Result
View All Result
  • Home
  • Category
    • Business
    • Culture
    • Economy
    • Lifestyle
    • Health
    • Travel
    • Opinion
    • Politics
    • Tech
  • Landing Page
  • Support Forum
  • Contact Us

© 2022 ZeroPlusFour - Latest News & Blog.

Welcome Back!

Login to your account below

Forgotten Password?

Retrieve your password

Please enter your username or email address to reset your password.

Log In
We use cookies on our website to give you the most relevant experience by remembering your preferences and repeat visits. By clicking “Accept All”, you consent to the use of ALL the cookies. However, you may visit "Cookie Settings" to provide a controlled consent.
Cookie SettingsAccept All
Manage consent

Privacy Overview

This website uses cookies to improve your experience while you navigate through the website. Out of these, the cookies that are categorized as necessary are stored on your browser as they are essential for the working of basic functionalities of the website. We also use third-party cookies that help us analyze and understand how you use this website. These cookies will be stored in your browser only with your consent. You also have the option to opt-out of these cookies. But opting out of some of these cookies may affect your browsing experience.
Necessary
Always Enabled
Necessary cookies are absolutely essential for the website to function properly. These cookies ensure basic functionalities and security features of the website, anonymously.
CookieDurationDescription
cookielawinfo-checkbox-analytics11 monthsThis cookie is set by GDPR Cookie Consent plugin. The cookie is used to store the user consent for the cookies in the category "Analytics".
cookielawinfo-checkbox-functional11 monthsThe cookie is set by GDPR cookie consent to record the user consent for the cookies in the category "Functional".
cookielawinfo-checkbox-necessary11 monthsThis cookie is set by GDPR Cookie Consent plugin. The cookies is used to store the user consent for the cookies in the category "Necessary".
cookielawinfo-checkbox-others11 monthsThis cookie is set by GDPR Cookie Consent plugin. The cookie is used to store the user consent for the cookies in the category "Other.
cookielawinfo-checkbox-performance11 monthsThis cookie is set by GDPR Cookie Consent plugin. The cookie is used to store the user consent for the cookies in the category "Performance".
viewed_cookie_policy11 monthsThe cookie is set by the GDPR Cookie Consent plugin and is used to store whether or not user has consented to the use of cookies. It does not store any personal data.
Functional
Functional cookies help to perform certain functionalities like sharing the content of the website on social media platforms, collect feedbacks, and other third-party features.
Performance
Performance cookies are used to understand and analyze the key performance indexes of the website which helps in delivering a better user experience for the visitors.
Analytics
Analytical cookies are used to understand how visitors interact with the website. These cookies help provide information on metrics the number of visitors, bounce rate, traffic source, etc.
Advertisement
Advertisement cookies are used to provide visitors with relevant ads and marketing campaigns. These cookies track visitors across websites and collect information to provide customized ads.
Others
Other uncategorized cookies are those that are being analyzed and have not been classified into a category as yet.
SAVE & ACCEPT
Are you sure want to unlock this post?
Unlock left : 0
Are you sure want to cancel subscription?