Search Insert Position – LeetCode Solution Java , Python 3, Python 2 , C , C++, Best and Optimal Solutions , All you need.

Given a sorted array of distinct integers and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.

You must write an algorithm with O(log n) runtime complexity.

Example 1:

Input: nums = [1,3,5,6], target = 5
Output: 2

Example 2:

Input: nums = [1,3,5,6], target = 2
Output: 1

Example 3:

Input: nums = [1,3,5,6], target = 7
Output: 4

Constraints:

• 1 <= nums.length <= 104
• -104 <= nums[i] <= 104
• nums contains distinct values sorted in ascending order.
• -104 <= target <= 104

C++ Search Insert Position LeetCode Solution

class Solution {
public:
    int searchInsert(vector<int>& nums, int target) {
     
        int low = 0, high = nums.size()-1;
        
        while(low<=high){
            int mid = low + (high-low)/2;
            
            if(nums[mid] == target) return mid;
            
            else if(nums[mid] > target) high = mid-1;
            
            else low = mid+1;
        }
        return low;
    }
};         

Java Search Insert Position LeetCode Solution

 public int searchInsert(int[] A, int target) {
        int low = 0, high = A.length-1;
        while(low<=high){
            int mid = (low+high)/2;
            if(A[mid] == target) return mid;
            else if(A[mid] > target) high = mid-1;
            else low = mid+1;
        }
        return low;
    }
 

Python 3 Search Insert Position LeetCode Solution

class Solution(object):
    def searchInsert(self, nums, target):
        """
        :type nums: List[int]
        :type target: int
        :rtype: int
        """       
        return len([x for x in nums if x<target])

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